C program for the power operation?

Answer 1

WARNING: This program will not work for x power y where the resulting value is greater than 32767. Example: 10 power 10 will give you an incorrect value.

#include <stdio.h>

int main()

{

int num, power,i,ans;

printf("Enter number and power\t");

scanf("%d%d",&num,&power);

ans=num;

for(i=1;i<power;i++)

ans=ans*num;

printf("%d to the power %d = %d",num,power,ans);

return 0;

}

Answer 2

#include<iostream.h>

#include<conio.h>

class abc

{

public:

int a,b,ans;

void show();

void display();

};

void abc::show()

{

cout<<"enter base value:- ";

cin>>a;

cout<<"enter power value:- ";

cin>>b;

}

void abc::display()

{

if(b==0)

{

cout<<1;

}

for(int i=0;i<=b;i++)

{

ans=ans*b;

}

cout<<"Answer is= "<<ans;

}

Answer 3

You can use the 'pow' function. From the 'man' page:

POW(3) Linux Programmer's Manual POW(3)

NAME
pow, powf, powl - power functions

SYNOPSIS
#include

double pow(double x, double y);
float powf(float x, float y);
long double powl(long double x, long double y);

Link with -lm.

DESCRIPTION
The pow() function returns the value of x raised to the power of y.