helicopter
Use the following algorithm (written in pseudocode). Let largest be the lowest possible real number. Let smallest be the greatest possible real number. Repeat while there is input... { Read real number r from input. If r is greater than largest then let largest be r. If r is less than smallest then let smallest be r. } End repeat. Let range be largest minus smallest. Output range.
#include #include #include int main(int argc, char *argv[]){int n, smallest, largest, sum, temp;if(argc < 2){printf("Syntax: foo val1[val2 [val3 [...]]]\n");exit(1);}smallest = largest = sum = atoi(argv[1]);for(n = 2; n < argc; n++){temp = atoi(argv[n]);if(temp < smallest) smallest = temp;if(temp > largest) largest = temp;sum += temp;}printf("Smallest: %i\nLargest: %i\nAverage: %i\n", smallest, largest, sum / (argc - 1));return 0;}
what is if(!(str[i]==32))
Implement these methods: public static int smallest(int[] arr) { int small = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] < small) small = arr[i]; return small; } public static int largest(int[] arr) { int large = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] > large) large = arr[i]; return large; }
program that take three decimal number as input and find the largest among them in assembly language
You find the the smallest and largest values. The interval is the largest minus the smallest.
The smallest is 0o0'0'' and the largest is 180o0'0''
Use the following algorithm (written in pseudocode). Let largest be the lowest possible real number. Let smallest be the greatest possible real number. Repeat while there is input... { Read real number r from input. If r is greater than largest then let largest be r. If r is less than smallest then let smallest be r. } End repeat. Let range be largest minus smallest. Output range.
the largest number - the smallest number
i dont have a clue find it out your self
The range is the distance from the smallest value to the largest value. This is equivalent to the largest value MINUS the smallest value. Therefore you subtract.
If possible, find the largest and smallest possible values of the variable under study. Then the range = Largest Value minus Smallest Value.
#include #include #include int main(int argc, char *argv[]){int n, smallest, largest, sum, temp;if(argc < 2){printf("Syntax: foo val1[val2 [val3 [...]]]\n");exit(1);}smallest = largest = sum = atoi(argv[1]);for(n = 2; n < argc; n++){temp = atoi(argv[n]);if(temp < smallest) smallest = temp;if(temp > largest) largest = temp;sum += temp;}printf("Smallest: %i\nLargest: %i\nAverage: %i\n", smallest, largest, sum / (argc - 1));return 0;}
take the largest number in the sample and subtract the smallest number that is the range
Find the smallest and the largest values/numbers. These form the range.
Subtract the smallest number from the largest number and you will get the distance from the smallest number to the largest number. That is the range. Ex: {-2 -4 -6 3 6 7 12} Smallest number is -6, largest number is 12. 12- (-6) = 12 + 6 = 18. The distance from the smallest number to the largest is 16
There are an infinite number of different decimals. If you have the whole list, then-- The smallest one is the one with the most zeros after the decimal point,or the smallest digit after the zeros if there's a tie.-- The largest one is the one with the most nines after the decimal point,or the largest digit after the nines if there's a tie.If there are less than an infinite number of decimals on your list, then-- The smallest one is the one with the smallest digit after the decimal point,or if it's a tie, the smallest digit in the second place after the decimal point,or of that's a tie, the smallest digit in the third place after the decimal point . . . etc.-- The largest one is the one with the largest digit after the decimal point,or if it's a tie, the largest digit in the second place after the decimal point,or if that's a tie, the largest digit in the third place after the decimal point . . . etc.As soon as you find the largest, find the next largest the same way, byignoring the first largest and finding the largest of the ones that are left.As soon as you find the smallest, find the next smallest the same way, byignoring the first smallest and finding the smallest of the ones that are left.This whole thing feels like trying to explain how to eat a carrot or tie a shoe.