C program to multiply two numbers without using arithmetic operator and using recursive function?

Answer 1

# include<stdio.h>

main()

{

int a,b,i:

int result=0;

printf("enter two numbers to be multipied");

scanf("%d%d",&A,&B);

for(i=1;i<=b;i++)

result=result+A;

printf("%d*%d=%d\n",a,b,result);

}

Answer 2

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

int x,y,mul;

clrscr();

printf("Enter the value of x and y\n");

scanf("%d %d",&x,&y);

a=sqrt(a);

mul=x<<a;

printf("mul=%d",mul);

getch(); (Qudrattullah Omerkhel)

}

Answer 3

//-------------This program is Created By the Robin ---------------------------

// Contact Me to Find more answer :- 9889857111-------------//

void main()

{

int a,b,c;

printf("Enter 2 numbers to multiply (smaller first): ");

scanf("%d %d",&a,&b);

c=0;

while(b!=0)

{

if(b&1!=0)c+=a;

b=b>>1;

a=a<<1;

}

printf("The product is %d",c);

}

Answer 4

Here is the code...

#include<stdio.h>

void main()

{

int a,b,c;

printf("Enter 2 numbers to multiply (smaller first): ");

scanf("%d %d",&a,&b);

c=0;

while(b!=0)

{

if(b&1!=0)c+=a;

b=b>>1;

a=a<<1;

}

printf("The product is %d",c);

}

Answer 5

Yes by left shifting as one of the numbers is divisible by 2.

11 * 4

int a = 11;

int b = 4 / 2;

a = (a << b);

a = 44;

There is another way. Multiplication is a quick way to to do addition.

4 * 4 = 16;

4 + 4 = 8

8 + 4 = 12

12 + 4 = 16

Answer 6

\* multiply the two numbers*/

#include<stdio.h>

#include<conio.h>

{

int a,b,c;

printf("Enter two numbers");

scanf("%d" ,&a ,&b);

c=a+b;

printf("multiplication=%d" ,c);

getch();

}

Answer 7

It is not possible to do anything on a computer without using operators. Computers perform all computations using a combination of operators and operands, nothing more, nothing less.

Conforming to the text of the question and assuming an operator is an infix operator as in a*b, a C program can call a function in a language other than C with numbers to be added. That would be a C program that adds without operators.

Even better, a C program calls an assembly language routine (any assembler on any machine) which will use its own version of an addition command to accomplish the addition, without using an operator at all :)