C program to reverse an array elements using dynamic memory allocation?

Answer 1

/* Write a C program to reverse the elements of a 1-D array using pointers. */

#include<stdio.h>

#include<conio.h>

#include<process.h>

void REVERSE(int *ptr1, int *ptr2, int n);

void main()

{

int X[30], m, i;

clrscr();

printf("\n\n\n\tEnter the size of Array (Less than 30):");

scanf("%d",&m);

if ((m > 30) (m < 2))

{

printf("\n\n\t\tERROR !!!!!!");

printf("\n\t\tENTER SIZE WITHIN GIEVEN FIELDS....TRY

AGAIN.");

getch();

exit(0);

}

clrscr();

printf("\n\n\n\tEnter the elements of Array :");

for(i=0;i<m;i++)

{

printf("\nElement %d:",i+1);

scanf("%d",&X[i]);

}

REVERSE(X,X,m);

printf("\n\n\n\n\tThe Reversed Array is:\n");

for(i=0;i<m;i++)

printf("\n\t\tElement %d: %d",i+1,X[i]);

getch();

}

void REVERSE(int *ptr1, int *ptr2, int n)

{

int *temp=NULL;

int i;

for(i=0;i<n;i++,ptr2++);

for(i=0,ptr2--; i<(n/2); i++,ptr1++,ptr2--)

{

*temp=*ptr1;

*ptr1=*ptr2;

*ptr2=*temp;

}

}

/************ PROGRAM ENDS ************/