C programming code for anagram

Answer 1

#include <stdio.h>

#include <ctype.h>

#define N 26 /* lenght of array */

int main()

{

char ch;

int count[N] = {0};

int x;

printf("Enter first word: ");

while ((ch = getchar()) != '\n')

{

if (isalpha(ch))

{

count[toupper(ch) - 'A']++;

}

}

printf("Enter second word: ");

while ((ch = getchar()) != '\n')

{

if (isalpha(ch))

{

count[toupper(ch) - 'A']--;

}

}

for (ch = 0; ch < N; ch++)

{

if (count[ch] != 0)

x = 1;

}

if (x == 1)

{

printf("The two words are not anagrams.\n");

}

else

{

printf("The two words are anagrams.\n");

}

return 0;

}