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The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7

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Heloise Parisian

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2y ago
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14y ago

pH =2.4

H+ = 10^-2.4 = 0.00398107171

OH- = 1X10^-14/H+

OH- = 2.51188643 x 10^-12

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Wiki User

14y ago

Much like calculating pH, you can calculate pOH. pOH = -log[OH-]

After that pH + pOH = 14. All you need to do is subtract and that will give the pH.

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9y ago

pH + pOH = 14.0 pH = 6.2 means pOH = 7.8 [OH-] = 10^-pOH = 10^-7.8 = 1.6 x 10^-8 M

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Q: Calculate the OH- of a solution that has a pH of 2.40?
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