HCl is a strong acid, so we assume that it completely breaks up into ions in solution.
HCl ----> H+ & Cl-
if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl-
pH = -log [H+]
pH = -log 0.01
pH = 2
To calculate the molarity of a solution from its pH, use the formula: pH = -log[H+]. In this case, pH 5.7 corresponds to [H+] = 1 x 10^-5.7 M. Given that HCl is a strong acid and dissociates completely in water, the molarity of HCl is also 1 x 10^-5.7 M.
The pH of a solution of HCl is calculated using the concentration of H+ ions. Since HCl dissociates completely in water, the concentration of H+ ions is equal to the concentration of HCl. First, calculate the concentration of HCl in the solution: 0.45g HCl / (36.46 g/mol) = 0.012 mol HCl. Then, divide the moles of HCl by the volume of the solution in liters to get the concentration in mol/L. Finally, calculate the pH using the formula pH = -log[H+].
The pH of a 1N HCl solution can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution. For a 1N solution of HCl, the concentration of H+ ions will be 1M, so the pH will be -log(1) = 0.
The pH of a 6M HCl solution is 0.
It solely depends on H+ concentration: each HCl gives one H+ , to calculate use pH = -log[H+] So, at [HCl]=1.0 >> pH= 0.0 at [HCl]=0.5 >> pH= 0.7 at [HCl]=0.1 >> pH= 1.0 at [HCl]=1.0*10-5 >> pH= 5.0 but don't ever use this simplified 'acid pH' calculus method when the answer comes close to (or exceeds) 6.5, 7 or 8 etc.
To calculate the molarity of a solution from its pH, use the formula: pH = -log[H+]. In this case, pH 5.7 corresponds to [H+] = 1 x 10^-5.7 M. Given that HCl is a strong acid and dissociates completely in water, the molarity of HCl is also 1 x 10^-5.7 M.
The pH of a solution of HCl is calculated using the concentration of H+ ions. Since HCl dissociates completely in water, the concentration of H+ ions is equal to the concentration of HCl. First, calculate the concentration of HCl in the solution: 0.45g HCl / (36.46 g/mol) = 0.012 mol HCl. Then, divide the moles of HCl by the volume of the solution in liters to get the concentration in mol/L. Finally, calculate the pH using the formula pH = -log[H+].
The pH of a 1N HCl solution can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution. For a 1N solution of HCl, the concentration of H+ ions will be 1M, so the pH will be -log(1) = 0.
HCl is a strong acid and dissociates completely. Therefore it can be found using the equation: ph= -log [H+]
The pH of a 6M HCl solution is 0.
It solely depends on H+ concentration: each HCl gives one H+ , to calculate use pH = -log[H+] So, at [HCl]=1.0 >> pH= 0.0 at [HCl]=0.5 >> pH= 0.7 at [HCl]=0.1 >> pH= 1.0 at [HCl]=1.0*10-5 >> pH= 5.0 but don't ever use this simplified 'acid pH' calculus method when the answer comes close to (or exceeds) 6.5, 7 or 8 etc.
To calculate the pH of a 0.001 mol/dm³ HCl solution, you use the formula pH = -log[H+]. For HCl, since it is a strong acid, it dissociates completely into H⁺ ions. Thus, the concentration of H⁺ ions in a 0.001 mol/dm³ HCl solution is also 0.001 mol/dm³. Taking the negative logarithm of 0.001 gives a pH of 3.
100 Liters? I will assume as much. Molarity = moles of solute/Liters of solution Molarity = 0.10 mole HCl/100.0 Liters = 0.001 M HCl -------------------------now, to find pH - log(0.001 M HCl) = 3 pH -----------------so, your acid is of 3 pH, which is to be expected at the volume od solution
The concentration of hydrogen ions in a solution with a pH of 3 is 1 x 10^-3 mol/L.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.