you have to learn chemistry
Find moles HCl. 5 g HCl (1 mole HCl/36.450 grams) = 0.1372 moles HCl Now, Molarity = moles of solute/Liters of solution Molarity = 0.1372 moles HCl/1 liter = 0.1372 M HCl Then. -log(0.1372 M HCl) = 0.9 pH ( you might call it 1, but pH can be off the scale ) -----------
100 Liters? I will assume as much. Molarity = moles of solute/Liters of solution Molarity = 0.10 mole HCl/100.0 Liters = 0.001 M HCl -------------------------now, to find pH - log(0.001 M HCl) = 3 pH -----------------so, your acid is of 3 pH, which is to be expected at the volume od solution
No, pH 2.0 HCl refers to the acidity level of the solution, while 0.1 M HCl refers to the molarity or concentration of the hydrochloric acid. The two terms describe different properties of the solution.
Molarity is the concentration of a solution, defined as moles per unit volume. Where, Molarity = moles / volume In this case the molarity of the HCl solution is 0.03 M The pH of this is calculated by the equation below pH = - log [H+] Where [H+] is the concentration of hydrogen ions/ protons present in the solution. As HCl only contains one hydrogen ion per molecule then the concentation of [H+] is 0.03 M Then the equation can be calculated (the minus sign is very important!) pH = - log 0.03 pH = 1.52 To summarise, Molarity of 0.03 M HCl solution is 0.03 M pH of 0.03 M HCl solution is 1.52
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
Find moles HCl. 5 g HCl (1 mole HCl/36.450 grams) = 0.1372 moles HCl Now, Molarity = moles of solute/Liters of solution Molarity = 0.1372 moles HCl/1 liter = 0.1372 M HCl Then. -log(0.1372 M HCl) = 0.9 pH ( you might call it 1, but pH can be off the scale ) -----------
100 Liters? I will assume as much. Molarity = moles of solute/Liters of solution Molarity = 0.10 mole HCl/100.0 Liters = 0.001 M HCl -------------------------now, to find pH - log(0.001 M HCl) = 3 pH -----------------so, your acid is of 3 pH, which is to be expected at the volume od solution
No, pH 2.0 HCl refers to the acidity level of the solution, while 0.1 M HCl refers to the molarity or concentration of the hydrochloric acid. The two terms describe different properties of the solution.
Molarity is the concentration of a solution, defined as moles per unit volume. Where, Molarity = moles / volume In this case the molarity of the HCl solution is 0.03 M The pH of this is calculated by the equation below pH = - log [H+] Where [H+] is the concentration of hydrogen ions/ protons present in the solution. As HCl only contains one hydrogen ion per molecule then the concentation of [H+] is 0.03 M Then the equation can be calculated (the minus sign is very important!) pH = - log 0.03 pH = 1.52 To summarise, Molarity of 0.03 M HCl solution is 0.03 M pH of 0.03 M HCl solution is 1.52
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
I think it'd be pH 7. Same amount of both, providing they are the same molarity!
Since it is an single proteolytic strong acid, the pH will be-log10(5.0 mol/l) = -0.7(Yes, it is a negative value, because the concentration is bigger than 1.0 )
The pH of 0.002 M HCl is approximately 2.3 assuming complete dissociation of HCl into H+ and Cl- ions. The calculation involves taking the negative base 10 logarithm of the concentration of H+ ions which is given by the molarity of the acid solution.
The answer depends on several unspecified variables, most importantly the final molarity of the solution, which depends on the final volume. You can calculate the value yourself using the formula: pH = -log[H+] where [H+] is the final concentration of H+ ions in solution. For HCl, [H+] is equal to molarity. So, for example, if you add 50.0 ml of 1.0M HCl to 950 ml of deionized water, your final concentation is: (50.0 ml/1000 ml) * (1.0M) = 0.05M Therefore: pH = -log[0.05] = 1.3
The pH of a 1N HCl solution can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution. For a 1N solution of HCl, the concentration of H+ ions will be 1M, so the pH will be -log(1) = 0.
The pH of a solution of HCl is calculated using the concentration of H+ ions. Since HCl dissociates completely in water, the concentration of H+ ions is equal to the concentration of HCl. First, calculate the concentration of HCl in the solution: 0.45g HCl / (36.46 g/mol) = 0.012 mol HCl. Then, divide the moles of HCl by the volume of the solution in liters to get the concentration in mol/L. Finally, calculate the pH using the formula pH = -log[H+].
HCl is a strong acid and dissociates completely. Therefore it can be found using the equation: ph= -log [H+]