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Calculate the pH of a solution prepared by diluting 3.0 mL of 2.5 M HCl to a final volume of 100 mL with H2O?
Because HCl is a strong acid, it dissociates completely to H + Cl. Therefore, 3.0 mL x 2.5 M HCl = 7.5 meq of H+ . In 100 mL of solution, this is 0.075 M H+. pH= - log [H] = - log (0.075) = - (-1.1) = 1.1 (two significant figures)
How would you prepare 1600 ml of a pH 1.50 solution using concentrated 12M HCl?
Start with the pH. pH is -log(H)=1.5 Solve for H (this is your concentration of hydrogen). This comes out to be .0316=[H]. This means there are .0316 mols of H in 1 liter of solvent. So now that we know this, we can use this equation MoVo=MfVf (o is initial, f is final, M is molar, V is volume) So plug in the numbers (.0316)(1.6)=(12)(Vf) Vf = .001813 L or 1.813 mL. So you'd take 1.813 mL of 12 M HCl and dilute it to 1600 mL This makes sense because 12M HCl has a very LOW pH, so diluting with such amount of solvent is necessary. Now that I have more time, I'll tell you how you want to approach this. The thing is all about the equation MoVo=MfVf. This equation is used for diluting. Now we have two of these values, we just need the other M to solve for volume of 12 M HCl. So how does pH relate to this problem (namely concentration)? We pH is a measure of concentration. That is -log[H]. So We must solve for [H]. Upon doing so, we then consider this: What happens when HCl dissociates? Well here it is HCl ====> H + Cl So for every mol of HCl, we get a mol of H. Therefore, [HCl]=[H] So there you have it!!
What is the pH of a 0.280 molar HCl solution?
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
Preparation of phosphate buffer pH 3?
To prepare a phosphate buffer at pH 3, you will need to mix monosodium phosphate (NaH2PO4) and disodium phosphate (Na2HPO4) in the appropriate ratios. The specific ratio will depend on the desired buffer capacity. You can start by dissolving the calculated amounts of NaH2PO4 and Na2HPO4 in distilled water, adjusting the pH using a strong acid like phosphoric acid, and finally bringing the volume to the desired final concentration.
What is the pH of a 4.3 x 10-2 M HCl is the solution?
p(x)=-log([x])So... pH=-log([H+])pH = 1.4
What is the pH of 10.0 mL of 0.0020 M HCl?
The pH of a 0.0020 M HCl solution is approximately 2.7. This is because HCl is a strong acid that completely dissociates in water to form H^+ ions, decreasing the pH of the solution.
How do you prepare 0.5M Tris-HCL pH 7.2?
To prepare 0.5M Tris-HCl pH 7.2, first calculate the amount of Tris base needed using the molecular weight of Tris (121.14 g/mol). Then dissolve the calculated amount of Tris base in water, adjust the pH to 7.2 using HCl while monitoring with a pH meter, and make up the final volume.
What is the pH of a 0.100 molar HCl solution?
The answer depends on several unspecified variables, most importantly the final molarity of the solution, which depends on the final volume. You can calculate the value yourself using the formula: pH = -log[H+] where [H+] is the final concentration of H+ ions in solution. For HCl, [H+] is equal to molarity. So, for example, if you add 50.0 ml of 1.0M HCl to 950 ml of deionized water, your final concentation is: (50.0 ml/1000 ml) * (1.0M) = 0.05M Therefore: pH = -log[0.05] = 1.3
Calculate the pH of a solution prepared by diluting 3.0 mL of 2.5 M HCl to a final volume of 100 mL with H2O?
Because HCl is a strong acid, it dissociates completely to H + Cl. Therefore, 3.0 mL x 2.5 M HCl = 7.5 meq of H+ . In 100 mL of solution, this is 0.075 M H+. pH= - log [H] = - log (0.075) = - (-1.1) = 1.1 (two significant figures)
What is the pH of a 6M HCl solution?
The pH of a 6M HCl solution is 0.
Solubility of Ambroxol Hcl in pH 6.8?
The solubility of Ambroxol HCl can vary depending on the specific conditions. Generally, Ambroxol HCl is more soluble in acidic pH than neutral pH. At pH 6.8, the solubility of Ambroxol HCl may be lower compared to acidic pH. Further experimental testing may be needed to determine the specific solubility at pH 6.8.
What is the pH of Na2HPO4?
For example, to obtain a solution with the pH=7,00 mix: 756 mL 0,1 M solution of Na2HPO4 with 244 mL of 0,1 M HCl solution.
A 10.0ml sample of the hcl solution was transferred by pipet to an erlenmeyer flask and then diluted by adding about 40ml of distilled water what is the h30 concentration and pH before titration?
The answer depends on the concentration in the original HCl-sol'n.Let this be Co (mol HCl/Litre). According to dilution 'law': Co.Vo=Cdiluted.VdilutedCdiluted = Co*10.0 ml / 50 mL = 0.20*Co mmol/ml = CdilutedHCl is a monoprotic strong acid, meaning [HCl]:[H3O+] = 1:1H3O+ = concentration HCl solution = Cdiluted = 0.20*Co mmol/ml= 0.20*Comol/LpH = -log10[H3O+] = -log10[0.20*Co] = 0.70 - log10[Co]
How would you prepare 1600 ml of a pH 1.50 solution using concentrated 12M HCl?
Start with the pH. pH is -log(H)=1.5 Solve for H (this is your concentration of hydrogen). This comes out to be .0316=[H]. This means there are .0316 mols of H in 1 liter of solvent. So now that we know this, we can use this equation MoVo=MfVf (o is initial, f is final, M is molar, V is volume) So plug in the numbers (.0316)(1.6)=(12)(Vf) Vf = .001813 L or 1.813 mL. So you'd take 1.813 mL of 12 M HCl and dilute it to 1600 mL This makes sense because 12M HCl has a very LOW pH, so diluting with such amount of solvent is necessary. Now that I have more time, I'll tell you how you want to approach this. The thing is all about the equation MoVo=MfVf. This equation is used for diluting. Now we have two of these values, we just need the other M to solve for volume of 12 M HCl. So how does pH relate to this problem (namely concentration)? We pH is a measure of concentration. That is -log[H]. So We must solve for [H]. Upon doing so, we then consider this: What happens when HCl dissociates? Well here it is HCl ====> H + Cl So for every mol of HCl, we get a mol of H. Therefore, [HCl]=[H] So there you have it!!
How do you prepare 0.1M tris HCl?
To prepare 0.1M Tris-HCl, dissolve 1.21 g of Tris (molecular weight 121.14 g/mol) in distilled water to make 100 mL of solution. Adjust the pH to 7.4 using HCl.
What is the pH of a 1.0x10-4m hcl solution?
- log(0.00450 M HCl)= 2.3 pH=======
What is the pH of a solution containing 6M HCl?
The pH of a solution containing 6M HCl is 0.
