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The answer depends on the concentration in the original HCl-sol'n.

Let this be Co (mol HCl/Litre). According to dilution 'law': Co.Vo=Cdiluted.Vdiluted

  • Cdiluted = Co*10.0 ml / 50 mL = 0.20*Co mmol/ml = Cdiluted
  • HCl is a monoprotic strong acid, meaning [HCl]:[H3O+] = 1:1
  • H3O+ = concentration HCl solution = Cdiluted = 0.20*Co mmol/ml= 0.20*Comol/L
  • pH = -log10[H3O+] = -log10[0.20*Co] = 0.70 - log10[Co]
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13y ago
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13y ago

Since the starting concentration of the (original) HCl solution wasn't given, only the C H A N G E in pH can be calculated, as well as some examples.

The dilution factor is (10ml + 40ml) / 10ml = 5.0.

Thus the [H3O+] is 5.0 times lower, so pH will increase.

Taking the negative logarithm (which is what pH is defined as) of this factor, pH will increase by +0.70 units.

Example:

  1. Original concentration 0.010 mol/L => pH = 2.0

    Diluted (5x) concentration 0.0020 mol/L => pH = 2.7

  2. Original concentration 0.50 mol/L => pH = 0.30

    Diluted (5x) concentration 0.10 mol/L => pH = 1.0

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Q: A 10.0ml sample of the hcl solution was transferred by pipet to an erlenmeyer flask and then diluted by adding about 40ml of distilled water what is the h30 concentration and pH before titration?
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