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Calculate the boiling point elevation of an aqueous solution of 0.0500 m CaCl2 Assume complete dissociation?
Wiki User
∙ 14y ago
CaCl2 dissociates to Ca2+ + 2Cl- so CaCl2 -> Ca2+ + 2Cl-
you have to know the value of Kb which they should tell you in the problem
so the equation would be like this m x Kb x i
i equals how many moles there are when it dissociates also known as the Von Hoff Factor look it up if you need it more specifically
m is the molality which is 0.05 in this case
so 0.05x3x the Kb
if you assume that this reaction takes place in water
the Kb is 0.52
actually i change my mind the Kb IS 0.52 because aqueous means dissolved in water.
sorry for the confusion but i really hope i helped
Wiki User
∙ 14y ago
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