Current = charge/time = 10/5 = 2 amperes
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
A flow of 7400 coulombs in 85 seconds represents a current of 87 amperes. One ampere is one coulomb per second, so divide 7400 by 85.
10/2 = 5 coulombs per second = 5 amperes.
Current = Charge / Time = 90 / 0.02 = 4500 Amperes
calulate the voltage of a battery that provides 20 joules of energy to every 5 coulombs of charge
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
The charge transferred in 25 minutes by a current of 500 mA is 750 coulombs. Amperes is defined as coulombs per second, so 500 mA is 0.5 coulombs per second. 25 minutes is 1500 seconds, so the charge is 750 coulombs.
A flow of 7400 coulombs in 85 seconds represents a current of 87 amperes. One ampere is one coulomb per second, so divide 7400 by 85.
10/2 = 5 coulombs per second = 5 amperes.
If you divide the charge by the time, you get the average current (in amperes).
Current = Charge / Time = 90 / 0.02 = 4500 Amperes
No electrical charge is "generated"; the charges are simply moved around. To calculate the amount of charge that flows past a given spot, multiply the current by the time. Don't forget to convert the time to seconds first.
Divide the coulombs by the amperes. The answer will be in seconds. The resistance is irrelevant in this problem.
Current is electrical charge flow, in coulombs per second. We simplify coulombs per second and call it amperes.
If you know the electric current, the flow of electric charge through an object, traveling through a circuit and how long the current is applied, you can calculate electrical charge using the equation for current Q = It in which Q is the total charge measured in coulombs, I is current in amps, and t is time that the ..
Current in amperes is coulombs per second, so 2 coulombs per second is 2 amperes.
For a steady flow of charge through a surface, the current I in amperes can be calculated with the following equation:I = Q/t where Q is the electric charge transferred through the surface over some time t. If Q and t are measured in coulombs and seconds respectively, I is in amperes. Thus: I = 0.24 coulombs / 15 msec I = 0.24 coulombs / 15 * 10^-3 sec I = 16 amps