A flow of 7400 coulombs in 85 seconds represents a current of 87 amperes.
One ampere is one coulomb per second, so divide 7400 by 85.
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
Current = charge/time = 10/5 = 2 amperes
10/2 = 5 coulombs per second = 5 amperes.
Current = Charge / Time = 90 / 0.02 = 4500 Amperes
I=0.4 A T=3hrs=10800 seconDs i=q/t q=It q=0.4*10800 q=4320Coulomb
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
Current = charge/time = 10/5 = 2 amperes
The charge transferred in 25 minutes by a current of 500 mA is 750 coulombs. Amperes is defined as coulombs per second, so 500 mA is 0.5 coulombs per second. 25 minutes is 1500 seconds, so the charge is 750 coulombs.
72 coulombs in 24 seconds is 3 amperes.One ampere is one coulomb per second.
10/2 = 5 coulombs per second = 5 amperes.
If you divide the charge by the time, you get the average current (in amperes).
Current = Charge / Time = 90 / 0.02 = 4500 Amperes
Current = charge / time Charge q = n * e e = 1.602 x 10^-19 C time given = 0.2 s Current = 0.5 A So I = n e / t Hence n = I * t / e Plug I, t and e. You would get required n ANS: 6.24 x 10^17 electrons
Divide the coulombs by the amperes. The answer will be in seconds. The resistance is irrelevant in this problem.
In an electronic circuit a capacitor can be used to block direct current. In general a capacitor stores electric charge. The charge in a capacitor is the voltage times the capacitance and that is also equal to the charging current times the time (all quantities in SI units - seconds, volts, amps, coulombs, farads)
The current is 50 Amperes, 5/.1=50Coul/sec.
No electrical charge is "generated"; the charges are simply moved around. To calculate the amount of charge that flows past a given spot, multiply the current by the time. Don't forget to convert the time to seconds first.