The current is 50 Amperes, 5/.1=50Coul/sec.
Current = charge / time Charge q = n * e e = 1.602 x 10^-19 C time given = 0.2 s Current = 0.5 A So I = n e / t Hence n = I * t / e Plug I, t and e. You would get required n ANS: 6.24 x 10^17 electrons
1 Ampere = 1 Coulomb per second0.25 A = 0.25 Coulomb per sec1 minute = 60 seconds20 minutes = (20 x 60) = 1,200 seconds0.25 A for 20 minutes = (0.25 x 1,200) = 300 Amp-seconds = 300 Coulombs of charge
1 Ampere = 1 Coulomb/sec (225 Coulomb) / (5 sec) = 45 Coulomb/sec = 45 Amp.
1 Amp = 1 Coulomb/sec 3 Amps = 3 Coulomb/sec Time = (9 coul) / (3 coul/sec) = 3 seconds
The battery can move a charge of 100,000 coulombs through a potential difference of 12 volts, therefore the energy released is 12 x 100,000 coulombs, or 1.2 Megajoules. 100,000 coulombs is (for example) 10 Amps for 10,000 seconds, in other words 10 amps for 2.78 hours, so its capacity is 27.8 ampere-hours.
An electric current is the amount of electrons per unit time or seconds.
72 coulombs in 24 seconds is 3 amperes.One ampere is one coulomb per second.
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
A flow of 7400 coulombs in 85 seconds represents a current of 87 amperes. One ampere is one coulomb per second, so divide 7400 by 85.
Current = charge / time Charge q = n * e e = 1.602 x 10^-19 C time given = 0.2 s Current = 0.5 A So I = n e / t Hence n = I * t / e Plug I, t and e. You would get required n ANS: 6.24 x 10^17 electrons
10/2 = 5 coulombs per second = 5 amperes.
For a steady flow of charge through a surface, the current I in amperes can be calculated with the following equation:I = Q/t where Q is the electric charge transferred through the surface over some time t. If Q and t are measured in coulombs and seconds respectively, I is in amperes. Thus: I = 0.24 coulombs / 15 msec I = 0.24 coulombs / 15 * 10^-3 sec I = 16 amps
The charge transferred in 25 minutes by a current of 500 mA is 750 coulombs. Amperes is defined as coulombs per second, so 500 mA is 0.5 coulombs per second. 25 minutes is 1500 seconds, so the charge is 750 coulombs.
If you divide the charge by the time, you get the average current (in amperes).
Current = charge/time = 10/5 = 2 amperes
1 Ampere = 1 Coulomb per second0.25 A = 0.25 Coulomb per sec1 minute = 60 seconds20 minutes = (20 x 60) = 1,200 seconds0.25 A for 20 minutes = (0.25 x 1,200) = 300 Amp-seconds = 300 Coulombs of charge
Current = Charge / Time = 90 / 0.02 = 4500 Amperes