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Calculate the effective value of the acceleration of gravity at 6100m above the earth's surface?
Wiki User
ā 14y ago
Assuming all objects fall at the same pace at the same altitude, using Newton's formula of Gravity, F = G*m1*m2/r2.
G is the global gravity constant, m1 = 5.9736 × 1024 kg, m2 = 1kg (because it doesn't matter, all objects fall at the same pace, 1 is easier to calculate), and r2 = (earth's radius + 6100m)^2
After you put all those numbers, you get F =~ 9.8N. Since our object is 1kg of mass, that's also the acceleration (according to newton's 2nd law)
Wiki User
ā 14y ago
At a height of 6100m above the Earth's surface, the effective value of the acceleration of gravity would be slightly less than the value at the Earth's surface due to the increase in distance from the Earth's center. This decrease in acceleration is given by the formula: ( g' = g \left( \frac{R}{R+h} \right)^2 ), where g is the acceleration of gravity on the surface of the Earth (approximately 9.81 m/s^2) and R is the radius of the Earth (approximately 6371 km). By applying this formula, you can find the effective value of the acceleration of gravity at 6100m above the Earth's surface.
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What is the acceleration due to gravity near the surface of earth equal to?
The acceleration due to gravity near the surface of the Earth is approximately 9.81 m/s^2.
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The only factor needed to calculate change in velocity due to acceleration of gravity is time. This is because the change in velocity can be calculated using the formula: change in velocity = acceleration due to gravity x time.
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The value for acceleration due to gravity on the surface of the Earth is approximately 9.81 m/s^2.
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How much above the surface of earth does the acceleration due to gravity reduces by 36 percent of its value on the surface of earth radius of earth equals 6400 km?
The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.
How do you calculate mass if you are only given weight in Newtons?
Weight = (mass) x (local acceleration of gravity). Mass = (weight) / (local acceleration of gravity) If you know the weight and the local acceleration of gravity, you can calculate the mass. Anywhere on or near the surface of the earth, the local acceleration of gravity is about 9.82 meters per second2 . As an example, an object with a weight of 9.82 newtons has a mass of one kilogram.
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The acceleration due to gravity near the surface of the Earth is approximately 9.81 m/s^2.
What is the only factor needed to calculate change in velocity due to acceleration of gravity?
The only factor needed to calculate change in velocity due to acceleration of gravity is time. This is because the change in velocity can be calculated using the formula: change in velocity = acceleration due to gravity x time.
What is equivalent of acceleration due to gravity?
The equivalent of acceleration due to gravity on the surface of the Earth is approximately 9.81 m/s^2.
How much above the surface of earth does the acceleration due to gravity reduces by 36 percent of its value on the surface of earth radius of earth equals 6400 km?
The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.
How to calculate the acceleration of falling body?
The acceleration of a falling body due to gravity on the surface of the Earth is approximately 9.81 m/sĀ². This is a constant value and is independent of the mass of the object. The acceleration can be calculated using the formula: acceleration = (force due to gravity) / (mass of the object), where the force due to gravity is given by F = m * g, where m is the mass of the object and g is the acceleration due to gravity.
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What is the acceleration dues to gravity near the surface of the earth?
The acceleration due to gravity near the surface of the Earth is approximately 9.81 m/s^2.
What is the numerical value in a meters per second squared of the acceleration of an object experiencing a true free fall?
The acceleration of an object by gravity depends on where the object is. The AVERAGE acceleration of gravity on the Earth is 9.81 m/s². Effective gravity on the Earth's surface varies by around 0.7%, from 9.7639 m/s2 on the Nevado Huascarán mountain in Peru to 9.8337 m/s2 at the surface of the Arctic Ocean.Of course if you drop an object on other bodies - such as the moon or Mars, the acceleration is MUCH different that it is on Earth.
Why is the acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on earths surface?
The acceleration due to gravity is lower on Mars compared to Earth because Mars has less mass than Earth, which means it exerts less gravitational pull. This difference in mass causes Mars to have a weaker gravitational field and therefore a lower acceleration due to gravity.
