I don't like when people just use WikiAnswers and Yahoo Answers to get their homework solved, but I'll just help you with this one question.
Formula for M: Molarity = moles of solute / liters of solution
Plug in the numbers you have. 0.70 is the amount of moles in the solute, and 1 is the amount of liters in the solution.
M = 0.70 mol / 1 L = 0.70 M
Hope this helps. Try doing your homework yourself next time, though. :) - Jessica
.35M
1.82
Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )
Yes, vinegar is a dilute solution of acetic acid, which is a type of carboxylic acid. Carboxylic acids are organic compounds containing a carboxyl group (–COOH), and acetic acid has the chemical formula CH3COOH.
Ch3cooh
The term for a compound containing hydrogen and a nonmetal dissolved in water is an acid. Acids release hydrogen ions (H+) when dissolved in water, making the solution acidic. Examples include hydrochloric acid (HCl) and acetic acid (CH3COOH).
Acetic Acid (CH3COOH) and Water. It's a dilute solution..usually 5%
Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )
Given that the pH of a 0.12 M solution of acetic acid (CH3COOH) is 3.0, you can calculate the concentration of H+ ions in the solution using the formula pH = -log[H+]. Once you have the concentration of H+ ions, you can use it to calculate the concentration of CH3COO- ions using the ionization constant expression for acetic acid (CH3COOH) and then determine the Ka value.
Vinegar is a 4-6% solution of Acetic acid (CH3COOH).
Yes, vinegar is a dilute solution of acetic acid, which is a type of carboxylic acid. Carboxylic acids are organic compounds containing a carboxyl group (–COOH), and acetic acid has the chemical formula CH3COOH.
At equal concentrations, the pH of HCl solution will be lower than that of CH3COOH solution due to HCl being a stronger acid than CH3COOH. This is because HCl fully dissociates in water to produce more H+ ions compared to the partial dissociation of CH3COOH.
Ch3cooh
The symbol equation for the reaction between ethanoic acid and silver nitrate solution is: CH3COOH + AgNO3 -> AgCH3COO + HNO3
Vinegar is a weak solution of acetic acid.
Acetic acid, CH3COOH, and Sodium Acetate, (CH3COOH-)(Na+).
The term for a compound containing hydrogen and a nonmetal dissolved in water is an acid. Acids release hydrogen ions (H+) when dissolved in water, making the solution acidic. Examples include hydrochloric acid (HCl) and acetic acid (CH3COOH).
Vinegar is 5 to 10% solution of acetic acid CH3COOH in water.
Vinegar is a water solution of acetic acid (CH3COOH), usually 9 % concentration.