Calculate the pH of solution formed when 30cm3 of 0.125m naoh are reacted with 25cm3 of 0.15m hcl at 298k?

Answer 1

No. of mol of NaOH used = 30/1000 x 0.125 = 0.00375
No. of mol of HCl used = 25/1000 x 0.15 = 0.00375

No. of mol of HCl used = No. of mol of NaOH used.
Hence, the resultant solution will be neutral. pH ~ 7.
(NaCl formed is a neutral salt, does not undergo any form of salt hydrolysis)