The formula you are looking for is R = W/I x I.
the actual filament itself in a light bulb has the most resistance,this is why it glows and produces light,the rest of the bulb is sufficiently engineered to carry the voltage and current applied to it without producing too much heat.
Volt (V) = Resistance (R) times Current (I) therefor R = V / I 30 Ω = 3V / 0.1A
Do you mean why is the voltage in a circuit lower after the light bulb than before it? If so, it's because the light bulb filament has electrical resistance. When an electrical current flows through a resistance, there is a voltage drop across the resistance (Ohm's law).More fundamentally, the light bulb is producing light, which is a form of energy. The voltage drop across the light bulb comes from the fact that electrical energy is being turned into light. If voltage didn't drop, you would be producing energy from nothing. Furthermore, if there were no voltage drop, your circuit would behave the same whether you had no light bulbs, one light bulb, or eighteen million light bulbs - something that clearly can't be the case.
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
A: HARD TO SAY because a bulb has different resistance as it warms up
there is no voltage and resistance
there is no voltage and resistance
An incandescent bulb has a filament that has a resistance. The value of the resistance determines the current that will flow for a given supply voltage. The heat generated by the current flowing through the filament gives off light. As the resistance of the filament decreases the current increases and you get more light.
By Ohm's law, resistance is voltage divided by current, so the resistance of a light bulb can be measured by observing the voltage across it simultaneously with observing the current through it. Interestingly, the hot resistance is significantly different that the cold resistance, so measuring resistance with an ohmmeter will not give a meaningful resistance. This is because the resistance of a light bulb has a positive temperature coefficient. Take a typical 60 W 120V light bulb, for instance... Its cold resistance is about 16 Ohms. Calculate current and power at 120 V and you get 7.5 A and 900 W. The truth is that at 60 W, the bulb pulls 0.5 A and has a resistance of 240 Ohms.
Ohm's law applies: Current = Voltage / Resistance As such if you double the resistance of the light bulb you end up with half as much current.
The bulb has resistance which then gets smal
how much resistance does a light bulb creat if iyt has a current of 25 mA around it in a 9 V circuit?
The current if the light bulbs are parallel is I= V/R where V is the voltage and R is the resistance of the bulb.
the actual filament itself in a light bulb has the most resistance,this is why it glows and produces light,the rest of the bulb is sufficiently engineered to carry the voltage and current applied to it without producing too much heat.
Yes, a light bulb is a source of light. When current is going through the filament the resistance generates enough heat that the filament glows, producing light.
The incandescent light bulb. The tungsten filament lights due to it's resistance of the current flowing through it.
If the two batteries are in series, add the voltages. Then use Ohm's Law to calculate the current (that is, divide the voltage by the resistance).