== == == == Assuming this inquiry is a request for information rather than related to a practical application, here is the answer: It will work but you probably won't like the results. You are not going to get the amount of light you should or probably want. I would hook up the proper size light, or the proper juice for the light. A 240 Volt rated tungsten filament lamp will glow dimly if 120 Volts are applied.
The resistance of the filament will limit the current to a level below that which will raise the filament temperature to high enough a level to glow fully bright.
The same thing would hold true if one applied 60 Volts to a 120 Volt lamp.
If you are contemplating installing a 240 Volt European fixture in the U.S. [the idea that may have motivated the question], there are manufacturers who make a 120 Volt lamp with a base for the 240 Volt fixture sockets. Yes, a 240 Volt incandescent lamp will work in a 120 Volt application, but you won't get half the light. You'll get a lot less than half, even though the applied voltage is half the rated voltage. There are hardly any sensible reasons to run a 240 Volt lamp in a 120 Volt application. <><><>
As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.
Before you do any work yourself,
on electrical circuits, equipment or appliances,
always use a test meter to ensure the circuit is, in fact, de-energized.
IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
Yes. The bulb will be slightly dimmer, but will last much longer. Most 145V bulbs are intended to be used in 120V exit signs. The reason for the higher voltage rating on the bulb is because it will last a long, long time when used at 120V.
You don't, at least, not legally.
A DFG base down 150W/120V lightbulb
It is 120V
Power is measured in Watts, power (Watts) = E (volts) x I (current - amps) current is determined by the internal resistance (R) of the lightbulb, the lower the resistance the more current will flow. 120v x 0.5a = 60W 120V x 0.83a = 100W the 100W lightbulb will draw more current We also have Ohm's law: E(volts) = I (amps) x R (ohms) Household voltage stays the same at 120v we have for a 100w lamp: 120v = I x R R = 120v/0.83 amps R = 144.6 ohms for a 60w lamp: 120v = I x R R = 120v/0.5 amps R = 240 ohms The higher watt lamp has lower resistance.
depends on the amp rating for the socket. amps times volts equals watts
No, the cord ends have different configurations to prevent this sort of thing from happening.
Household is 120/240 volts at 60Hz. The average wall socket is 120v 60Hz.
See discussion page for more.
Yes. Outlets are regulated at 110v. Use an overload circuit breaker to be on the safe side.
The average air compressor uses only about 120v. Which is the average house socket. Thus using about 400 Watts of power.
Most CFL bulbs will not work with a dimmer, but there are special ones made for dimmers. Assuming you find some that work, the number depends on the wattage of the bulbs and the rated amperage of the dimmer. To figure it out, you would take the total wattage and divide it by volts. ( 120V) for normal house hold) which will give you amps. Then you would do 15% of the amps the dimmer is rated for and subtract that from the total amps the dimmer. Lets say you have a 15 amp rated dimmer and some 20 watt bulbs. 15% of the dimmer amps would be 2.25 amps, minus from the rating would be 12.75 amps. That is the safe zone. Anything over that on anything rated for 15 amps is considered overloading and dangerous. Now a 20 watt bulb is around 0.17 amps. To be safe lets say .2 amps. That would mean you theoretically could put around 60 bulbs for that one dimmer. No one would recommend doing that nor is it practical. All of this is an example. No exact numbers can be calculated with the info given. If you don't know what you are doing then call a pro. Always deenergize the circuit before working on them, and remember all electricity can kill you regardless the voltage or amps so respect it.
No. If you plug something that needs 24 volt into a 120v socket you will probably ruin your device.
120v is what is in the socket at your house, your battery is at 12.6v. My guess is your battery would get hot and boil, releasing hydrogen which is explosive. And you run the risk of destroying many of your very sensitive computers, but more likely you would just pop your fuses.
Most dimmer switches work by turning the light off for a certain amount of time...a light bulb connected to 120V 60Hz actually turns off 120 times a second...If you have it turn off 60 times a second (and stay off longer each cycle) it appears to be dimmer...This is what SCRs and Triacs do...They turn AC voltage off for a period of time,while still swithing fast enough that your eye sees no flicker.
No. The neon sign is fed by a step-up transformer. Primary side 120V, secondary side 7500V. If you applied 240 to the primary side you would get 15000 volts on the neon tube. A flash over and then nothing. If you can find a transformer from 120V to 240V or 240V to 120V then you are good to go. Connect 240V to 240V side and you will get 120V out the other, connect the 120V side to the neon sign and you should have light. Transformer should be at least 100va. This will give you an output of .83 amps at 120V
I think I understand what you are asking. 3-phase motors usually are equipped with a starter or contactor, since all 3 hot wires need to be switched. The control voltage that runs the starters is 120V, because it's safer and also 120V switches and relays are cheaper. You would have a 480-120V transformer (called a control transformer) in the starter box to provide the 120V "control voltage". So the arrangement you describe would have two contactors, with two phases reversed between them. Energize one, and the motor runs forward. Energize the other, and it runs reverse. The switch sends 120V to each of the contactors, which are equipped with 120V coils.
120V takes less energy
Yes, it can!
p = v * i 75w = 120v * i i = 75w / 120v i = .625A v = i * R 120V = .625A * R R = 120V / .625A R = 192 ohm
In the US, it is between 110V Min and 120v Max
I would say yes.. household power in the US is 110 to 120V depending on location from sub station most devices are set up to operate anywhere in this range