Can a 240V lightbulb 25W work in a 120V socket and would it just be dimmer?
== == == == Assuming this inquiry is a request for information rather than related to a practical application, here is the answer: It will work but you probably won't like the results. You are not going to get the amount of light you should or probably want. I would hook up the proper size light, or the proper juice for the light. A 240 Volt rated tungsten filament lamp will glow dimly if 120 Volts are applied.
The resistance of the filament will limit the current to a level below that which will raise the filament temperature to high enough a level to glow fully bright.
The same thing would hold true if one applied 60 Volts to a 120 Volt lamp.
If you are contemplating installing a 240 Volt European fixture in the U.S. [the idea that may have motivated the question], there are manufacturers who make a 120 Volt lamp with a base for the 240 Volt fixture sockets. Yes, a 240 Volt incandescent lamp will work in a 120 Volt application, but you won't get half the light. You'll get a lot less than half, even though the applied voltage is half the rated voltage. There are hardly any sensible reasons to run a 240 Volt lamp in a 120 Volt application. <><><>
As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.
Before you do any work yourself,
on electrical circuits, equipment or appliances,
always use a test meter to ensure the circuit is, in fact, de-energized.
IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
Power is measured in Watts, power (Watts) = E (volts) x I (current - amps) current is determined by the internal resistance (R) of the lightbulb, the lower the resistance the more current will flow. 120v x 0.5a = 60W 120V x 0.83a = 100W the 100W lightbulb will draw more current We also have Ohm's law: E(volts) = I (amps) x R (ohms) Household voltage stays the same at 120v we have for a…
Most CFL bulbs will not work with a dimmer, but there are special ones made for dimmers. Assuming you find some that work, the number depends on the wattage of the bulbs and the rated amperage of the dimmer. To figure it out, you would take the total wattage and divide it by volts. ( 120V) for normal house hold) which will give you amps. Then you would do 15% of the amps the dimmer…
Most dimmer switches work by turning the light off for a certain amount of time...a light bulb connected to 120V 60Hz actually turns off 120 times a second...If you have it turn off 60 times a second (and stay off longer each cycle) it appears to be dimmer...This is what SCRs and Triacs do...They turn AC voltage off for a period of time,while still swithing fast enough that your eye sees no flicker.
No. The neon sign is fed by a step-up transformer. Primary side 120V, secondary side 7500V. If you applied 240 to the primary side you would get 15000 volts on the neon tube. A flash over and then nothing. If you can find a transformer from 120V to 240V or 240V to 120V then you are good to go. Connect 240V to 240V side and you will get 120V out the other, connect the 120V…
I think I understand what you are asking. 3-phase motors usually are equipped with a starter or contactor, since all 3 hot wires need to be switched. The control voltage that runs the starters is 120V, because it's safer and also 120V switches and relays are cheaper. You would have a 480-120V transformer (called a control transformer) in the starter box to provide the 120V "control voltage". So the arrangement you describe would have two…
Can you take single phase of 120V with a hot wire and a neutral step up to 480v and then step down to 2 phases of 120V or do you have to input 2 phases of 120v to get 240V out?
How can you wire one half of a 20 amp 120 v duplex wall socket to run 240 volts over 2 legs 2 separate 120 v legs?
You can't. I'm not sure exactly what you're trying to do, but the way it is written is not possible. It seems you might want to use half of a duplex receptacle for 120 and half for 240. This would not be code compliant, nor would it make sense. A plug designed for 240v will not even fit into a 120v receptacle. You need a 240 volt receptacle rated for the amperage you will need…
It depends on the voltage source. watts = voltage * voltage / resistance and amps = voltage / resistance example 1: To produce 600W from a 120V source, you need a resistor of size 120V*120V/600W = 24 Ohm. This would pull 120V/24 Ohm = 5 amps. example 2: To produce 600W from a 240V source, you need a resistor of size 240V*240V/600W = 96 Ohm. This would pull 240V/96 Ohm = 2.5 amps.