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The lowest possible temperature is -273.15 C which equated to '0'K. Therefore, temperature -273K cannot exist. No -ve K temperatures exist.
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Molecular motion in a gas is the minimum possible at?
-273K
Do you expect li2- to exist in the gas phase?
Yes, it will exist in the gas phase.
If Eight moles of hydrogen gas at 0 are forced into a steel cylinder with a volume of 300 ml what is the pressure of the gas in the cylinder?
Answer: 597.4 ATM PV=nRT P=8(0.08206)(273K)/0.3L P=597.4 ATM
What can exist as a solid liquid and gas?
water
What state of matter does hydrogen exist in?
Gas
Molecular motion in a gas is the minimum possible at?
-273K
At o degrees Celsius or 273k is nitrogen a solid or a gas?
solid
The active mass of 22.2 lit of carbondioxied gas at 273k is?
0.045 mol L 0.5. Mol.
What is lower criticism?
-273k
What is 273K in Celsius?
273K = -0.15ºCUse this equation to convert Kelvin to degrees Celsius/Centigrade: [°C] = [K] - 273.15
What is lower critical temperature?
-273k
Do you expect li2- to exist in the gas phase?
Yes, it will exist in the gas phase.
A temp of 273k is the temp at which water?
Freezes.
Which of these represents the freezing point of water in correct SI units 0C 273K 32F or 32C 0F 273K?
0°c
What is the pressure of 7.85g of CO2 at 27.0c in a volume of 19.6L?
You can use the Ideal Gas Law or the Combined Gas Law. PV/T = PV/T ---- left are usually labeled (1) and right (2) to show different conditions left P = unknown, V = 19.6L, T = (273+27)K right P= 760 torr or 1 amt, V = 22.4 L, T = 273K --- all are standard P(19.6L)/300K = 1atm(22.4L)/273K --- solve for P P = (1 atm)(22.4L)(300K)/ [(273K)(19.6L)] do the math --- get the answer.
How much volume does 1 mole of a gas occupy at NTP?
PV=nRT. So at ntp P=1bar. If n= 1mole. R= .082. T=273K. Then 1V=1.273 .082. v=22.44 l of gas
If Eight moles of hydrogen gas at 0 are forced into a steel cylinder with a volume of 300 ml what is the pressure of the gas in the cylinder?
Answer: 597.4 ATM PV=nRT P=8(0.08206)(273K)/0.3L P=597.4 ATM
