Well I doubt it would be able to hold a charge of that density in air. When a sphere of radius 1cm is charged to such a high level, the electric field will be far larger than the dielectric strength of air. Hence, a breakdown voltage will be achieved and electrons will flow even through air. It's the same principle that lightning works on. 1 coulomb is a huge amount of charge, and the surface charge density in this case will be too high for air to take. So, a sphere of radius 1 cm cannot hold 1 Coulomb of charge.
Yes, a metallic sphere of radius 1 cm can hold a charge of 1 coulomb. The amount of charge a conductor can hold is not dependent on its size but rather on its capacitance. For a spherical conductor, the capacitance (C) is directly proportional to the radius (r), so a larger radius would be able to hold more charge for the same potential difference.
No, the charge held by a solid metal sphere and a hollow sphere of the same diameter would be the same. In both cases, the charge resides on the outer surface of the sphere due to the principle of electrostatic equilibrium.
When a sphere is cut into cross sections, the shape formed is a circle. This is because all cross sections of a sphere will be circular in shape, regardless of the angle or position of the cut.
OK, so I can't include MathML or images or TeX so I'm struggling to answer this question. Here's a verbal description of the equation V = ((PI^(n/2)) * r^n)/G((n/2)+1) where PI is 3.14159... G() is the Gamma Function (complex factorial) and ^ indicates "to the power of". Hope that helps. Source: Eqn 20 , p453 of Shannon's paper "Communication in the Presence of Noise"
To find the volume of a silo, you can use the formula for the volume of a cylinder, which is V = πr^2h, where r is the radius of the silo base and h is the height of the silo. Measure these dimensions and plug them into the formula to calculate the volume.
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A metal sphere of radius 1 centimeter will not hold a charge of 1 coulomb. The electric field generated from the metal sphere of radiusÊat 1 centimeter will break down and neutralize any charges.
touch it with a charged object....
inner core
inner core
A sphere of radius R surround a point charge Q, located at its center afind the electric flux ?
The radius of a sphere joins the center of the sphere to its circumference.
The radius of a sphere is equal distance from the center of the sphere to all points within the sphere.
bidyogammes
Treat the 3D sphere as a 2D circle. The radius for the sphere is the same radius as for the circle. No matter where on the sphere you place a mark, the distance (radius) from the mark to the centre of the sphere will always be the same as the circle.
The volume of a sphere with a radius of 4cm is about 268cm3
The volume of a sphere with a radius of 2cm is about 33.5cm3
The radius of a sphere is 1/2 of its height.