Yes, if it has a non-zero component along some other line - usually, but not necessarily orthogonal.
Huh?I have been kicking around your question in my mind for five minutes trying to figure out an answer or a way to edit your question into an unambiguous form, but I'm stumped. I don't know what you mean by "zero component along a line."If you look at the representation of a vector on paper using a Cartesian coordinate system -- in other words, one using x and y axes -- the orthogonal components of the vector are the projections of the vector on the x and y axes. If the vector is parallel to one of the axes, its projection on the other axis will be zero. But the vector will still have a non-zero magnitude. Its entire magnitude will project on only one axis.But a vector must have magnitude AND direction. And if it has zero magnitude, its direction cannot be determined.Still trying to make heads or tails out of your question.......If you draw a random vector on a Cartesian grid, it will have an x component and a y component, which are both projections of the original vector upon the axes. However, it could also be represented by projecting it onto a new set of orthogonal axes -- call them x' and y' -- where the x' axis is oriented to be parallel to the original vector and the y' vector is perpendicular to it. In that case, the x' component will have a magnitude equal to the magnitude of the original vector -- in other words, a non-zero value along a line parallel to the x' axis -- and a zero magnitude in the y' direction.
No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.
Vector b would be along the z axis, it could have any magnitude.
Their directions are perpendicular.
Acting simultaneously along the same line and in the same direction, they have the same effect as a single vector in that direction with a magnitude of 13 N.
Huh?I have been kicking around your question in my mind for five minutes trying to figure out an answer or a way to edit your question into an unambiguous form, but I'm stumped. I don't know what you mean by "zero component along a line."If you look at the representation of a vector on paper using a Cartesian coordinate system -- in other words, one using x and y axes -- the orthogonal components of the vector are the projections of the vector on the x and y axes. If the vector is parallel to one of the axes, its projection on the other axis will be zero. But the vector will still have a non-zero magnitude. Its entire magnitude will project on only one axis.But a vector must have magnitude AND direction. And if it has zero magnitude, its direction cannot be determined.Still trying to make heads or tails out of your question.......If you draw a random vector on a Cartesian grid, it will have an x component and a y component, which are both projections of the original vector upon the axes. However, it could also be represented by projecting it onto a new set of orthogonal axes -- call them x' and y' -- where the x' axis is oriented to be parallel to the original vector and the y' vector is perpendicular to it. In that case, the x' component will have a magnitude equal to the magnitude of the original vector -- in other words, a non-zero value along a line parallel to the x' axis -- and a zero magnitude in the y' direction.
No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.
At what angle should a vector be directed to so that its x component is equal to its y component
Unless the vector is one dimensional, or only valued along one base in a multidimensional space, in which case the magnitude is equal to it's components, a vector's magnitude has to be greater than its components.
Vector b would be along the z axis, it could have any magnitude.
Nothing
Their directions are perpendicular.
opposite direction.
Speed is the rate of which an object is moving altogether and is a scalar quantity and thus only requires a magnitude and is found by the use of the formula speed=distance/time SI unit = m.s-1 Velocity is the rate of which a object is moving in a given direction, so is vector quantity and both a magnitude and direction are required found by the formula velocity=displacement/time SI unit = m.s-2
No. The answer does assume that "components" are defined in the usual sense - that is, a decomposition of the vector along a set of orthogonal axes.
Any physical quantity which has both direction and magnitude is called a vector. A quantity must also obey the 'Triangle law of vector addition' to be called as a vector. For example displacement is a vector, u can say a person moved 5 km (magnitude) along west(direction). But electric current is not a vector, it has magnitude and its direction is from +ve terminal to -ve terminal but it doesn't obey triangle law. Rather currents are added as scalars.
Acting simultaneously along the same line and in the same direction, they have the same effect as a single vector in that direction with a magnitude of 13 N.