I Rather not think that you can buy 2 farad capacitor and no the terminals must follow polarity guidelines.
micro farad
No. The large farad capacitors are not designed to pass a lot of current. They are intended for ultra-low current applications such as memory retention in a CMOS type device.
Only electrolytic capacitors (tantalum capacitors are a type of electrolytic capacitor) are polarized.0.001 farad = 1000 microfaradThis is a value that is too large for any practical capacitor except an electrolytic, so yes it will be polarized.
I imagine 2200 is the value and usual is in microfarad a one farad will be a huge capacitor to be used in electronics.
(a) what is the total capacitance of this arrangement (B) the charge stored on each capacitor (C) the voltage across the 50 micro farad capacitor and the energy stored in it. 20v and 20+30+50 micro farad
about 500 uF
Farad is the basic unit for capacitance. The MFD is an abbreviation for microfarad, which is one-millionth of a farad. The capacitance of a 50 MFD capacitor is one 50 millionth of a farad.
micro farad
The SI unit of capacitance is the farad. 1 farad is 1 coulomb per volt.
The Farad is a measure of how much electric charge is accumulated on the capacitor. Named after Michael Faraday
When used in car audio applications, a 1 farad capacitor is usually about 6" long and about 2.5-3" in diameter.
It takes 1 farad for every 1000 watts so u need 2 farads.
500K is 500 000 µ Farad so it's ½ a Farad
No. The large farad capacitors are not designed to pass a lot of current. They are intended for ultra-low current applications such as memory retention in a CMOS type device.
Only electrolytic capacitors (tantalum capacitors are a type of electrolytic capacitor) are polarized.0.001 farad = 1000 microfaradThis is a value that is too large for any practical capacitor except an electrolytic, so yes it will be polarized.
I imagine 2200 is the value and usual is in microfarad a one farad will be a huge capacitor to be used in electronics.
Since the total capacitance for capacitors in parallel is the sum of the individual capacitances. I'm sure that you can work it out for yourself!