I want to assmue the the readers of this answer have know the details theory and calculations about Mohr method if not u can refer to Any analytical text for reference. Well, Bromide and Chloride can not be determine simultaneously in a sample using Mohr method , the reason be that the indicator use for each of them is different. and there will be problem in the procedure if ones try to determine both simultaneously.
To determine Chloride Ion, Ammonium or Potassium Thiocynate is used as indicator and the sample must be neutral or slightly acidic. while Eosin indicator is use for the determination of Bromide Ion and the same neutral solution is prefer for this purpose, the solution must be adjusted to neutral either by adding small amount of Nitric acid or by adding small amount of carbonate as the case maybe.
But, in the determination of each of them Silver Nitrate is use for the titration of both and this is the similarity they shared and the experimental procedure is quite the same.
Olajire Mojeed
I may be off, but it has something to do with thermodynamics. The silver reacts well with chlorine and bromide, but when it comes to iodide, i would guess that the dG is too low leaving the iodide in solution. Also, if you look at the solubility of silver iodide, it is VERY high in water which doesn't give you the chance to create the precipitate needed for use in the Mohr method. Silver Chloride - white precipitate Silver Bromide - ? precipitate. Silver Chromate - red good luck.
(mass /volume)x100
We can find chlorides content as sodium chloride from 500 ppm with out any difficulty. p v rao
Crystallisation from solution, flotation, or electrostatic separation from suitable minerals.
good
Cupric bromide
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Examples: silver chloride, silver fluoride, silver iodide, silver bromide, silver astatide, silver sulfide, silver nitrate etc. For silver halogenides a method of preparation is the reaction between silver nitrate and a salt containing the halogen.
if u have sodium chloride solution just heat it..water will get evaporated leaving only sodium chloride
K+ and Cl- react to form KCl (potassium chloride)
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I may be off, but it has something to do with thermodynamics. The silver reacts well with chlorine and bromide, but when it comes to iodide, i would guess that the dG is too low leaving the iodide in solution. Also, if you look at the solubility of silver iodide, it is VERY high in water which doesn't give you the chance to create the precipitate needed for use in the Mohr method. Silver Chloride - white precipitate Silver Bromide - ? precipitate. Silver Chromate - red good luck.
Silver chloride is insoluble in water; filtration is a simple method.
which method will be used to separate sodium chloride and aluminium particals
Filtration
aqueous precipitation
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