The balanced chemical equation would be K4FeC6N6 + KMnO4 + H2SO4 = KHSO4 + Fe2SO43 + MnSO4 + HNO3 + CO2 + H2O.
FeS is Iron II Sulfide Fe2S3 is Iron III Sulfide
Fe2S3
Fe2(SO3)2 I don't think the above answer is right...I believe it is Fe2S3
Iron has a charge of +3 and Sulfur has a charge of -2, so iron III sulfide is: Fe2S3
The formula of iron (III) sulfide is Fe2S3, showing that each formula unit contains two iron atoms. The gram formula unit mass for iron (III) sulfide is 207.87, and the gram atomic mass of iron is 55.847. Therefore, the fraction by mass of iron in iron (III) sulfide is 2(55.847)/207.87 or about 0.5373, and the grams of iron in 130 g of iron (III) sulfide is 0.5373 X 130 or 69.9 grams, to the justified number of significant digits.
The chemical formula is... Fe2S3
The chemical formula for Fe3 combined with S2 is Fe2S3.
Formula: Fe2S3
Applying heat to the mixture causes a chemical reaction to occur: 2Fe + 3S -> Fe2S3
2Fe + 3s = Fe2S3
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
ferric indicates the iron is +3 as opposed to +2 for ferrous sulfide indicates that there is sulfur with a -2 charge the formula is Fe2S3 two iron ions with a +3 = +6 3 sulfur ions with a -2 = -6 -6+6 = 0
iron + sulphur -> iron sulphide Fe + S -> FeS
FeS is Iron II Sulfide Fe2S3 is Iron III Sulfide
Formula: Fe2S3
Ionic
Iron (|) Sulfide