Iron (|) Sulfide
IUPAC: Lead(IV) oxide old fashioned: Plumbic oxide (plumbous oxide would be PbO.)
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
Oxalic Acid is the old name for ethanedioic acid. Its structure is HO(O=)C - C(=O)OH
Preferred IUPAC name: Carbon monoxide
Iupac name of COCl2
IUPAC: Lead(IV) oxide old fashioned: Plumbic oxide (plumbous oxide would be PbO.)
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
Formula: Fe2S3
Iron(III) sulfide (Fe2S3) breaks down into iron(III) oxide (Fe2O3) and sulfur dioxide (SO2).
Oxalic Acid is the old name for ethanedioic acid. Its structure is HO(O=)C - C(=O)OH
If you think to chemical symbol of an element this is standardized after IUPAC rules.
Preferred IUPAC name: Carbon monoxide
Firdt of all the question should read ' Write the IUPAC name of the next homologue of CH3OH? Note the word and the spelling. The next homologue is CH3CH2OH (Ethanol).
Fesub2 S
Iupac name of COCl2
Ferrous Sulfide = Iron (III) Sulfide Both -> Fe2S3