No, and neither can the amplified output of a vacuum tube.
This is a particular transistor amplifier configuration. In general, the input signal is applied to the base, the collector is connected to a supply voltage, and the output is taken between the emitter and power supply common. One of the characteristics of the emitter follower is the output voltage "follows" the input, but the output is reduced by the Vbe voltage (the voltage drop between base and emitter, approximately 0.7 V for a silicon bipolar transistor).
In a two stage RC coupled amplifier, the two transistors are identical and a common power supply is used. The input is provided to the first stage of the amplifier where it is amplified and this output is used as input for the second stage. This is amplied once again by the other transistor in the second stage and the final output is obtained. There will be a 180 degree phase shift after the first stage amplification which is nullified by the 180 degree phase shift of the second stage amplification.Thus, we obtain an output which is an amplified signal of the input and is in phase with the input signal.
ac is not used because it produces distortion in the output. and also in the transistor the Q point is not able to be fixed by using ac supply. Q point gives the quality output to the amplifiers
A common-emitter (CE) transistor amplifier circuit typically includes a NPN transistor, a biasing resistor network, an input coupling capacitor, and an output coupling capacitor. The input signal is fed into the base of the transistor through the coupling capacitor, while the collector is connected to a power supply through a load resistor. The emitter is usually grounded or connected to a resistor. This configuration allows for voltage amplification, where the output is taken from the collector.
In a CMOS (Complementary Metal-Oxide-Semiconductor) circuit, a high output from a CMOS gate indicates that the output transistor (typically the PMOS transistor) is turned on, allowing current to flow from the supply voltage (V_DD) to the output node. This high output state effectively charges the load capacitance connected to the output, bringing the voltage at the output node close to V_DD. Conversely, the NMOS transistor is off, preventing any current flow to ground, thus maintaining the high state. The combination of these actions allows the CMOS gate to efficiently drive the load while consuming minimal power.
Power amplifierPower supply regulatorSwitching power supply chopperetc.
To convert an NPN signal to a PNP signal, you can use an inverter circuit, typically implemented with a transistor or a logic gate. For a simple transistor-based solution, connect the NPN transistor's collector to the power supply, its emitter to the load, and the base to the NPN signal through a resistor. When the NPN is on (high signal), it will turn off the PNP transistor, resulting in a low output, and vice versa, effectively inverting the signal.
1900
A class AB amplifier of the complementary transistor type has two transistors in series. Both transistors can change the resistance. If the upper transistor, a npn type, has minimum resistance and the lower transistor, a pnp type, has maximum resistance, the output voltage is near the supply voltage. One transistor is totally open and has zero current, the other transistor is totally closed and has zero voltage. Working together both transistors can set the output to any voltage between 0 and supply voltage. The class AB efficiency maximum is 100% minus the bias-power, see for example D. M. Snider, "A Theoretical Analysis and Experimental Confirmation of the Optimally Loaded and Overdriven RF Power Amplifier", 1966. Today the overdriven class AB amps are called class D.
There is competitive supply,if an increase in the output of one commodity requires a reduction in the output of another commodity.
transistor
A: Dissimilar metal will exhibits a voltage output like thermocouple materials. But no current does not flow not unless there is a force to make it flow on a circuit or transistor