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queue of 8086 microprocessor is 6 bits
The 8086/8088 is a CISC based architecture.
Assembly
lxi h,0091h lda 0090hmvi b,03hcmp mjm 0015hinx hdcr bjnz 0008hsta 00a0hhltmov a,minx hjmp 0008h
Maybe you mean the prefetch queue?
Describe with block diagram interfacing of adc with 8086?Read more: Describe_with_block_diagram_interfacing_of_adc_with_8086
As port A is used as an output port, control word for 8255 is 80H.Stepper Motor Control Program:6000H Excite code DB 03H, 06H,09H, OCH : This is the code sequence for clockwise rotationSubroutine to rotate a stepper motor clockwise by 360° - Set the counts:MVI C, 32H : Set repetition count to 50ıοSTART: MVI B, 04H : Counts excitation sequenceLXI H, 6000H : Initialize pointerBACK1: MOV A, M : Get the Excite codeOUT PORTA : Send Excite codeCALL DELAY : WaitINX H : Increment pointerDCR B : Repeat 4 timesJNZ BACK lDelay Subroutine:Delay: LXI D, CountBack: DCX DMOV A, DORA EJNZ BackRET
Pin 28 on the 8086/8088 is M/IO-, in minimum mode. The equivalent pin on the 8085 is IO/M-, and has opposite polarity.
the question is not clear. the chip with which 8086 has to be interfaced should be mentioned. for example, interfacing 8086 and 8087( NDP) or 8086 and 8255( PPI) or 8086 and 8259( PIC) or 8086 and 8089( IOP) But to make the answer complete I would like to mention 2 references 1.Douglas Hall, "Multiprocessors and Interfacing , Programming and Hardware", Tata Mcgraw-Hill.1999, second edition. 2.John Uffenback, "8086/88 Interfacing, Programming and Design", 1987, PHI.
The 8086/8088 is a 16 bit computer running on a 20 bit address bus. Processes use a segmented memory architecture to access one of four 64kb memory segments from a physical space of 1mb.
assembly language program for sorting an array using 8086 microprocessor.
write program to concatenating two sting in 8086 assembly language
One many find this answer on YouTube. One also may find out how to write ascending order programs using an 8086 microprocessor by looking at the owners manual.
stack segment register
In 8086 pipeline concept was introduced bcoz in 8086 we started using a buffer space which fetches the instruction at the same time when CPU processes
What is the need of segments in 8086 micro-processor? Explain how the address of an instruction is calculated in 8086 using segment register
we can measure the water level