The 8086/8088 is a 16 bit computer running on a 20 bit address bus. Processes use a segmented memory architecture to access one of four 64kb memory segments from a physical space of 1mb.
The 8086/8088 does not have memory management, at least in the style of virtual memory, like its successors.
the principle function of memory interfacing is to enable the microprocessor to read or write into a register of the memory chip
Its MRDC (memory read control) it is a maximum mode pin in 8086 microprocessor
It is mightily referring to Microprocessor 8086 . I think you saw "8086 microprocessor". The 8086 is nothing it indicates the number of microprocessor same as Digital or analog ic's . 8086 microprocessor has 20 Address buses and 8 data buses which has 1 Mb inbuilt memory for performing several type of airthmatical and logical operation.
Memory to memory access is certainly possible in the 8086/8088 microprocessor. Look at the repeated string copy instructions.
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Describe with block diagram interfacing of adc with 8086?Read more: Describe_with_block_diagram_interfacing_of_adc_with_8086
The 8086 microprocessor has 40 pins.
Pin 28 on the 8086/8088 is M/IO-, in minimum mode. The equivalent pin on the 8085 is IO/M-, and has opposite polarity.
The communication between input and output device is called interfacing.
While executing a program, the microprocessor needs to access memory frequently to read instruction codes and data stored in memory and the interfacing circuit enables that access.
The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.
The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.