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Can you take phenylephrine with 10 mg lisinopril
The Dog can run
pH=-lg[H+][H+]=10-pHWith pH=2.0:Corrected:[H+]= 10-pH = 10-2.0 = 0.010 M HCL
Phenylephrine 10 mg manufactured by Perrigoa nasal decongestant used as a decongestant.
Nooooooooooooooo!!!!!!!! that is not isay not for dogs you ask your vet to tell you what to give your dog but dont give it human pills
To prepare a 1 micro mole solution of phenylephrine in 1 mL of distilled water, you will need to know the molar mass of phenylephrine and use it to calculate the required amount of phenylephrine powder. Here are the steps to prepare the solution: Determine the molar mass of phenylephrine: The molar mass of phenylephrine is 203.28 g/mol. Calculate the mass of phenylephrine needed: Since you want a 1 micro mole solution, which is equivalent to 1 x 10^-6 moles, you can use the formula: Mass (g) = Moles x Molar mass Mass (g) = 1 x 10^-6 moles x 203.28 g/mol Mass (g) = 0.00020328 g Therefore, you will need 0.00020328 grams of phenylephrine. Weigh out the required amount of phenylephrine: Use a digital balance to accurately measure 0.00020328 grams of phenylephrine powder. Transfer the phenylephrine powder to a clean and dry container, such as a vial or test tube. Add 1 mL of distilled water to the container containing the phenylephrine powder. Ensure that the water completely dissolves the powder by gently swirling or stirring the solution. Once the phenylephrine is completely dissolved, your 1 micro mole solution of phenylephrine in 1 mL of distilled water is ready for use. Note: It is important to handle chemicals and measurements with care and follow proper laboratory safety protocols while preparing solutions.
Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.
1N HCL is the same as 1 Molar HCl. You take the # of H ions and multiply by the molarity to get the Normality. Usually you buy HCl in concentrated form which is 12 Molar or 12 Normal HCL. You need to dilute the concentrated HCl to get the reduced concentration. Use the formula Molarity Initial x Volume Initial = Molarity Final x Volume Final ex. 12 M HCL x 10 ml = 1 M x 120 ml. So take 10 ml of concentrated HCl and add enough water to make 120 ml. This will give you 120 ml of 1 M (which is 1N) HCl. Venkat Reddy
Oddities San Francisco - 2012 Give the Dog His Bones 2-10 was released on: USA: October 2013
Concentrated HCl is typically 36.5% industrially. It is thus almost exactly 10 Molar.
By 10-fold dilution
37% HCl = { [ 37 (gHCl) / 100 (g sol'n) ] / 36.46 (gHCl/molHCl) } * 1,18 (g sol'n/mL sol'n) * 1000 (mL/L) = about 12 M HClTo prepare V Litres of 10M sol'n you should dilute [10*V]/12 Litre of 37% HCl solution to the total volume of V. Be very carefull with this addition of water.