No. An interface can only be implemented.
According to a beginner's book on Java, an interface can't have constructors. Also, the interface itself can't contain the method implementation.
dim obj as object obj = new object();
To instantiate a object, we use the new keyword in Java, which creates an object in memory.
A constructor in a class is one of the first pieces of code to be executed when you instantiate a class. The purpose of constructors is to have code that initialize the class and prepare the variables that may be required by the class...
we can make object of interface but in abstract we can not make object of it interface ab= new Classs(): in interface we maintain multiple inhetence by use of obj of interface we if inherit two class have same fun then we give the name of that interface and call the pertucular that fun interface ab= new class() ab.add(); but in Astract Class we cannot make object of it only class class wich inherit it can make object class ab2= new Class(); and by obj we call function of drived class ob2.add();
maybe
there would just be one instance of the object no matter how many times you instantiate it.
Yes. An abstract class is a conceptual class (an incomplete class) that provides a generic interface for two or more actual classes (the derived classes). For instance, a shape is not an actual object, nor is a mammal. They are simply a type of object; a conceptual object. A square is an actual type of shape, just as a golden Labrador is a specific breed of dog, an actual mammal. The conceptual classes merely provide a generic interface to the actual object, but do not have enough information to implement that interface. For instance, all shapes can be drawn, but without knowing what type of shape to draw, the conceptual shape cannot implement the draw method, it can only provide the interface. By declaring the shape::draw method to be pure-virtual, you not only ensure that you cannot instantiate a shape by itself (it is merely an abstraction), you also ensure that all the derivatives of the shape class provide a specific implementation of that interface.
No. You can declare a dynamic array without specifying a length, but in order to physically instantiate (either by using malloc or by using object-oriented construction) you must provide a length.
The using statement defines a scope at the end of which an object will be disposed. You create an instance in a using statement to ensure that Dispose is called on the object when the using statement is exited. A using statement can be exited either when the end of the using statement is reached or if, for example, an exception is thrown and control leaves the statement block before the end of the statement. The object you instantiate must implement the System.IDisposable interface. IDisposable is a very special interface. It is meant to be used with the "using" key word so it is very different than most any other interface as it has compile time support. It is meant for _exception safe_ deterministic cleanup of resources.
An object is simply an instance of a class. #include<iostream> class my_object {}; int main() { my_object X; // instantiate an instance of the class my_object, identified as X. }
When you inherit you typically override and specialise the virtual methods of the base class. With delegation, you embed a member object in your class and provide an interface (often a simplified interface) to that embedded object. Each embedded object takes care of itself, the container merely provides an interface and delegates the calls to the object itself.