Ohm's Law: Voltage = Current times Resistance
Some say so.
Resistance is measured in ohms.By Ohm's law, resistance is voltage divided by current, which is (joules per coulomb) divided by (coulombs per second), which is joules-seconds divided by coulombs squared. (It is easier to just say ohms.)
How about the same number of metres in a kilometre? Like say 1000
by the ohms law we can clearly say that the current is the ratio of voltage to the resistance.as the resistance is doubled the current should be halved.
according to ohms law V=IR where V=voltage I=current R= resistance so simply we can say that as I decreases R has to increase to maintain V.
Your question is incomplete. What you meant to say is "What is the voltage drop of a 1.2K Ohm resistance?" (an Ohm is a unit of measurement, a resistor or resistance is measured in ohms.) The answer is, it depends on the current flowing through the circuit. Use the formula V=IR where V is the voltage, I is the current in amps, and R is the resistance in ohms.
In the US, there is no law to determine how much a single man or anyone else needs to live on. There are guidelines and there are regulations for distribution of public funds to individuals but no law stating an amount a given individual needs.
Impossible to say without knowing the voltage
30 ohmsAnswerAn incandescent lamp doesn't obey Ohm's Law, because the ratio of voltage to current changes as the supply voltage is varied. All you can say is that, when the applied voltage is 9.0 V, then the resistance will happen to be 30 ohms. If you change the applied voltage to some other value, then you will find the resistance will have changed too. Ohm's Law isn't a universal law; in fact, most materials and circuit devices do not obey Ohm's Law, and tungsten, from which lamp filaments are manufactured, is an example of a metal that does not obey Ohm's Law (we call them 'non-linear' or 'non-ohmic')
Ohms Law: V = IR (or equivalently, I = V/R) if voltage is held constant, then when resistance goes up, current goes down, and vice-versa. Say for instance, the voltage is 10 Volts, and resistance is 5 Ohms. That means the current is 2 Amps. (2 = 10/5) If the resistance is raised to 10 Ohms, then the current drops to 1 Amp. (10 = 10/1)
Though it is tempting to say the difference is 2 ohms (8 ohms minus 2 ohms equals 6 ohms), lets look at some things. The 6 ohms is 3/4ths the resistance of the 8 ohms. If the resistances are loads, the 6 ohm load will draw 1/3rd more current than the 8 ohm load. The 8 ohm load will draw 3/4ths as much as the 6 ohm load. Those are some differences between 6 ohms and 8 ohms.
Your question is very confusing. When you say, 'meter', what type of meter? The only safe meter you can connect to a wall outlet is a voltmeter which will measure the actual voltage across the line and neutral (as opposed to the 'nominal' value). Then you bring in the subject of 'Ohm's Law' without explaining what you are trying to find. You need to rephrase the question so that it is clear what you are asking.