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If there is a potential difference of 12 V across a resistor with 0.25 A current in it the resistance if the resistor is?
Resistance (Ohms) = Potential Difference (Volts) / Current (Amps) So, 12/0.25 = 48 Ohms.
A circuit contains two devices that are connected in parallelIf the resistance of one of these device is 12 ohms and the resistance of the other device is 4 ohms the total resistance of the two divice?
For resistances in parallel, total effective resistance is [ 1 divided by (1/R1 + 1/R2 + 1/R3 + . . . . . etc.) ]For two resistors, this expression can be massaged to show that the net effective resistance is(R1 R2) / (R1 + R2).(12 x 4) / (12 + 4) = 48/16 = 3 ohms.
Do I need transformer for 800 feet 240v electric power line?
You may need to step up the voltage to minimize the power loss / voltage dip at the end of the 800 feet depending on: 1. the type of cable used (the higher resistance, the large cables would be required to not do this) 2. the amperage that you will need to draw. The voltage drop in the wires is due to the I^2*R losses in the cable. If your cable has a resistance of 1 ohm over 800 feet, and you draw 5 amps (so your load resistance is R = V/R = 240 / 5 = 48 ohms), the actual current delivered will be (I = V / R = 240 / 49) 4.9 amps, and the voltage at the end of the 800 feet will be (240 - 4.9*1) 235 volts. voltage is probably fine for whatever equipment you're using. If used continuously, the 800 ft of cable would waste 210kWh of energy/yr (15-35 dollars/year). If you need 20 amps, the load resistance would be (240 / 20) 12 ohms, current delivered to the load would be (240/13) = 18.5, and the voltage at the end of the 800 feet would be (240 - 18.5*1) 222 volts. This might be too low, depending on the equipment you're using and if you're area has a naturally low voltage to begin with. If used continuously, the 800 ft of cable would waste ~3,000kWh of energy/yr (180-450 dollars/year). As your question is written, a straight yes or no cannot be given. I hope the above explains enough to give you the knowledge you need to determine this on your own.
When a 3 ohm resistor draws a current of 4 A when hooked up to a battery of unknown voltage what is the battery's voltage and what is the power dissipated by the resistor?
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
How many volts to run a 48 Volt club car electric motor?
If a 48 Volt club car electric motor requires 48 volts, then it should be given a 48 volt power source, or something close to it. Too many more volts and it may burn out; not enough volts and it may not run or it will try to draw too much power and burn out the power supply.
How do you calculate the current flow through a parallel circuit with three lamps each of 48 ohms?
To calculate the current in the parallel circuit we need the concept of ohms law, V=IR we know the resistance, R=48 ohms voltage will be constant as 220-230 volts so, I= V/R = 230/48 = 4.791 A Add currents of three lamps, ie., I = 14.375
What would the voltage be in a DC circuit if there were a current flow of 6 A and a resistance of 8 ohms?
Ohms Law! E=IR Voltage equals current times resistance. Get out the old calculator...
How many ohms does a 194 12 volt bulb pull?
To find the resistance in ohms of a 194 12-volt bulb, you can use Ohm's Law (R = V/I). The 194 bulb typically has a current rating of about 0.25 amps. Using this information, the resistance would be approximately 48 ohms (R = 12V / 0.25A).
If there is a potential difference of 12 V across a resistor with 0.25 A current in it the resistance if the resistor is?
Resistance (Ohms) = Potential Difference (Volts) / Current (Amps) So, 12/0.25 = 48 Ohms.
What is the resistance value for LED bulb in 12v DC circut?
The resistance value for an LED bulb in a 12V DC circuit can vary depending on the specific LED bulb used. Generally, LEDs have very low resistance values due to their semiconductor nature. It is more common to use a current-limiting resistor in series with the LED to control the current and prevent damage to the LED.
What is the current in a 12volt circuit that has 9 ohms of resistance?
Ohm's Law: Current equals voltage divided by resistanceIf the two 3 ohm resistors are in series, then 12 volts divided by 6 ohms is 2 amperes.If the two 3 ohm resistors are in parallel, then 12 volts divided by 1.5 ohms is 8 amperes.WARNING: In the first case, this is 24 watts or 12 watts per resistor. In the second case, this is 96 watts or 48 watts per resistor. Exercise great care if you intend to duplicate this in the lab, i.e. do not think for even a split second that a 1/4 watt resistor is going to be able to handle this power without burning up and causing a fire.
What is the amount of current that flows through an electrical pathway with a resistance of 48 and voltage of 240v?
5amps of current will flow it
A vacuum cleaner is plugged into a 120.0-V socket and uses 3.0 A of current in normal operation when the back emf generated by the electric motor is 72.0 V Find the coil resistance of the motor?
To find the coil resistance of the motor, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). In this case, the voltage drop across the coil resistance is the difference between the supply voltage and the back EMF: 120.0 V - 72.0 V = 48.0 V. So, the resistance of the coil is 48.0 V / 3.0 A = 16.0 ohms.
A circuit contains two devices that are connected in parallelIf the resistance of one of these device is 12 ohms and the resistance of the other device is 4 ohms the total resistance of the two divice?
For resistances in parallel, total effective resistance is [ 1 divided by (1/R1 + 1/R2 + 1/R3 + . . . . . etc.) ]For two resistors, this expression can be massaged to show that the net effective resistance is(R1 R2) / (R1 + R2).(12 x 4) / (12 + 4) = 48/16 = 3 ohms.
A complete circuit contains two parallel-connected devices ana a generator for providing the electromotive force the resistance of the first device is 12 ohms the resistance of the second device is 4?
According to Ohm's law of resistance in parallel, 1/RT=1/R1+1/R2+1/R3... so 1/RT=1/12+1/4=1/12+3/12=4/12=1/3 and 1/(1/3)=3.The total resistance of the two devices is 3.There is a simpler special case formula for two resistances in parallel:* RTot = (R1R2) / (R1 + R2) In this case this it would give us (12 x 4) / (12 + 4), or 48 / 16 which equals 3 ohms.3 ohms
What is the resistance of the 12 volt circuit and has a measured current 0.25 A?
R = E/I = 12/0.25 = 48 Ω
Why BTS operated at -48 Volts?
All telephone exchanges use -48V DC Power supply. The negative potential is used to prevent electrolysis deposition at Battery terminals. Telephone normally work with about 30ma current driving a line impedence of about 1600 ohms (to drive about 5KM distance). Hence 30ma*1600 ohms=48 volts.
