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Voltage can be calculated using Ohm's Law:

Voltage = Current (A) x Resistance (Ω)

Voltage = 4A x 3Ω = 12 Volts


Therefore, the battery is a 12 Volts.






The power dissipated is Voltage x Current



Power = 4A x 12V = 48 Watts

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Related Questions

How can I find the energy dissipated in the resistor?

To find the energy dissipated in a resistor, you can use the formula: Energy (current)2 x resistance x time. This formula calculates the energy dissipated in the resistor based on the current flowing through it, the resistance of the resistor, and the time the current flows.


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No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.


Is a battery a resistor if not what is?

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What power is dissipated by an 8.2 k resistor if a current of 0.005 amps pass's through the resistor?

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How do you measure current without an amp meter?

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What is the formula for calculating the power dissipated in a resistor, given the current flowing through it and the resistance value, known as the i2r power?

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What is series connection?

You have two resistors, each with resistance of 12Ω, and a 12-volt battery. 1). The resistors are in series across the battery. ..... A. voltage across each resistor ..... B. current through each resistor ..... C. power dissipated by each resistor ..... D. total power delivered by the battery 2). The resistors are in parallel across the battery. ..... A. voltage across each resistor ..... B. current through each resistor ..... C. power dissipated by each resistor ..... D. total power delivered by the battery ============================================ 1). ... A. 6 volts ... B. 0.5 Amp ... C. 3 watts ... D. 6 watts 2). ... A. 12 volts ... B. 1 Amp ... C. 12 watts ... D. 24 watts


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P = I^2 x R] P = 0.2^2 x 100 P = 4 W