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Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What else can I help you with?
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
What is equivalent wattage when different wattage resistors are connected in parallel?
In order to determine this, it will be necessary to find which resistor 'maxes out' at the lowest voltage. This can be found using the equation Vi=sqrt (Pi*Ri) for each resistor, where Pi is the power rating of resistor i and Ri is the value of resistor i. Once this is found, the power dissipation of each other resistor can be found using the equation Pi=(Vl^2)/Ri, where Vl is the voltage that maxes out the resistor which maxes out at the lowest voltage, and Ri is the resistance of each resistor. The equivalent power rating would then be the sum of the power dissipated across each resistor.
Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What is the power dissipated in the Ohm resistor?
Power dissipated is always Volts times Amps. W= V*I because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value; W= V^2/R or W= I^2*R.
What is the power dissipated by a 1.2 Kilohm resistor if the voltage drop across the resistor is W volts?
The power dissipated by a resistor can be calculated using the formula ( P = \frac{V^2}{R} ), where ( P ) is the power, ( V ) is the voltage drop across the resistor, and ( R ) is the resistance. For a 1.2 kilohm resistor (or 1200 ohms), the power dissipated would be ( P = \frac{W^2}{1200} ) watts. Thus, the power dissipated depends on the square of the voltage drop across the resistor divided by 1200.
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
If two resistors of equal value are connected in parallel with each other. The power dissipated by the two resistors will be equal to the sum of the power dissipated by each resistor true or false?
True. When two resistors of equal value are connected in parallel, the total power dissipated by the circuit is indeed the sum of the power dissipated by each resistor. Since they have the same resistance and are subjected to the same voltage, each resistor will dissipate the same amount of power, and their combined power will equal twice that of one resistor.
If the voltage dropped across a resistor increases by a factor of 10 the power dissipated by the resistor is?
The power dissipated by a resistor is given by the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage across the resistor and ( R ) is its resistance. If the voltage increases by a factor of 10, the new power can be expressed as ( P' = \frac{(10V)^2}{R} = \frac{100V^2}{R} = 100P ). Therefore, the power dissipated by the resistor increases by a factor of 100.
Ac power that is converted to heat in a resistor is known as?
real power (as opposed to imaginary power, which is not dissipated)
What is the formula for calculating the power dissipated in a resistor, given the current flowing through it and the resistance value, known as the i2r power?
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
What power is dissipated by an 8.2 k resistor if a current of 0.005 amps pass's through the resistor?
.205 watts or 205 mw
What is the power dissipated by a resistor with a current of 2 amps and a resistance of 1000 ohms?
I = 2A R = 1000Ω Power Dissipated P = I2R = (2A)2(1000Ω) = 4000W Voltage across resistor V = IR = (2A)(1000Ω) = 2000V
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
What is the power dissipated by a resistor with a current of 0.02 A adn a resistance of 1000 ohms?
Power dissipated = I2R 0.022 x 1000 = 0.4 watts
How do you determine the amperage given the voltage and power dissipated?
Like Ohm's Law, the formula for calculating power is a simple product of two quantities. It is given by the formula P = VI, where V is the voltage in volts and I is the current in amperes (or simply amps). So, if you know the value of any two of the quantities, you can easily calculate the third with simple arithmetic. For example, if the current flowing through a resistor is two amps and the voltage drop across that resistor is five volts, the power dissipated by the resistor is, P = VI = 5 volts * 2 amps = 10 watts. If you are given the power and the voltage, you can easily find the current. For example, if you are told that the voltage drop across a resistor is five volts and is dissipating 10 watts, the current through the resistor is 10 watts/5 volts = 2 amps.
