Like Ohm's Law, the formula for calculating power is a simple product of two quantities. It is given by the formula P = VI, where V is the voltage in volts and I is the current in amperes (or simply amps). So, if you know the value of any two of the quantities, you can easily calculate the third with simple arithmetic. For example, if the current flowing through a resistor is two amps and the voltage drop across that resistor is five volts, the power dissipated by the resistor is, P = VI = 5 volts * 2 amps = 10 watts. If you are given the power and the voltage, you can easily find the current. For example, if you are told that the voltage drop across a resistor is five volts and is dissipating 10 watts, the current through the resistor is 10 watts/5 volts = 2 amps.
To answer this question the voltage must be given.
Amperage in a conductor is primarily regulated by the voltage across the conductor and the resistance of the conductor itself, as described by Ohm's Law (I = V/R). When voltage increases, amperage increases, provided the resistance remains constant. Conversely, higher resistance results in lower amperage for a given voltage. Additionally, factors such as temperature and the material properties of the conductor can also influence resistance and thus affect amperage.
If a secondary voltage is given across a particular resistive load in a series of known resistive loads, multiply the voltage by the ratio of the total load to the measures load to get total voltage. Example: You have a series of a 200 ohm resistor to a 100 ohm resistor. The votage measured across the 100 ohm is 2 volts. 200 + 100 = 300. 300 / 100 = 3. 2 X 3 = 6. Total Voltage in the circuit is 6V
To determine the amperage for 9000 watts, you need to know the voltage at which the power is being consumed. The formula to calculate amperage is Amps = Watts / Volts. For example, if the voltage is 120V (typical for household circuits in the US), the amperage would be 9000 watts / 120 volts = 75 amps. However, if the voltage is different, such as 240V, then the amperage would be 9000 watts / 240 volts = 37.5 amps.
You can't convert volts to amperes. Those are quite different units; that would be like converting, say, meters to seconds.
The amperage of a motor is governed by the voltage that the motor operates on. Without a voltage given, an answer can not be given.
To answer this question the supply voltage and the amperage of the load must be given.
Divide the power in watts by the voltage in volts to get the current in amps.
To answer this question the voltage must be given.
Amperage in a conductor is primarily regulated by the voltage across the conductor and the resistance of the conductor itself, as described by Ohm's Law (I = V/R). When voltage increases, amperage increases, provided the resistance remains constant. Conversely, higher resistance results in lower amperage for a given voltage. Additionally, factors such as temperature and the material properties of the conductor can also influence resistance and thus affect amperage.
If a secondary voltage is given across a particular resistive load in a series of known resistive loads, multiply the voltage by the ratio of the total load to the measures load to get total voltage. Example: You have a series of a 200 ohm resistor to a 100 ohm resistor. The votage measured across the 100 ohm is 2 volts. 200 + 100 = 300. 300 / 100 = 3. 2 X 3 = 6. Total Voltage in the circuit is 6V
To determine the amperage for 9000 watts, you need to know the voltage at which the power is being consumed. The formula to calculate amperage is Amps = Watts / Volts. For example, if the voltage is 120V (typical for household circuits in the US), the amperage would be 9000 watts / 120 volts = 75 amps. However, if the voltage is different, such as 240V, then the amperage would be 9000 watts / 240 volts = 37.5 amps.
Wire sizing of a feed conductor is based on the amperage that a device draws. To calculate amperage from KVA a voltage of the supply has to be stated. Without this voltage and whether the transformer is single or three phase an answer can not be given.
Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.
Wire sizing is based on the motors full load amperage. The amperage can be calculated but a voltage has to be stated. I = W/E. Amps = Watts/Volts. Restate the question with a voltage and an answer can be given.
To answer this question the voltage and the amperage of the cap must be stated. Then the termination letters can be given.
The power dissipated by a resistor is given by the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage across the resistor and ( R ) is its resistance. If the voltage increases by a factor of 10, the new power can be expressed as ( P' = \frac{(10V)^2}{R} = \frac{100V^2}{R} = 100P ). Therefore, the power dissipated by the resistor increases by a factor of 100.