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What is the power dissipated by a resistor with a current of 0.02 A adn a resistance of 1000 ohms?
Power dissipated = I2R 0.022 x 1000 = 0.4 watts
What is the formula for calculating the power dissipated in a resistor, given the current flowing through it and the resistance value, known as the i2r power?
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What is the power dissipated by a resistor with a current of 0.02 A and a resistance of 1000 ohms?
Power = I2 R = (0.02)2 x (1,000) = 0.4 watt
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
How do you calculate power loss from a resistor?
The power dissipated across a resistor, or any device for that matter, is watts, or voltage times current. If you don't know one of voltage or current, you can calculate it from Ohm's law: voltage equals resistance times current. So; if you know voltage and current, power is voltage times current; if you know voltage and resistance, watts is voltage squared divided by resistance; and if you know current and resistance, watts is current squared times resistance.
At what level will typical resistors burn out?
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
What is the power dissipated by a 1.2 Kilohm resistor if the voltage drop across the resistor is W volts?
The power dissipated by a resistor can be calculated using the formula ( P = \frac{V^2}{R} ), where ( P ) is the power, ( V ) is the voltage drop across the resistor, and ( R ) is the resistance. For a 1.2 kilohm resistor (or 1200 ohms), the power dissipated would be ( P = \frac{W^2}{1200} ) watts. Thus, the power dissipated depends on the square of the voltage drop across the resistor divided by 1200.
What is the formula of power being dissipated in a resistor?
Voltage times current. You obtain current from the division of voltage and resistance, so: I[A] = U[V] / R[ohm] and P[W] = U[V] * I[A] it follows, that P[W] = U[V] * (U[V] / R[ohm]) = U[V] ^ 2 * R[ohm] So, voltage squared divided by resistance will give you the power that will be dissipated in a resistor. Whether the resistor will take that abuse is up to its power dissipation rating, however.
What is power disipated in R if R equals 300 ohms and current equals 20 mA?
The power dissipated in a resistor can be calculated using the formula P = I^2 * R, where P is power, I is current, and R is resistance. Plugging in the values given, we get P = (0.02 A)^2 * 300 ohms = 0.012 watts. Therefore, the power dissipated in the 300-ohm resistor with a current of 20 mA is 0.012 watts.
If two resistors of equal value are connected in parallel with each other. The power dissipated by the two resistors will be equal to the sum of the power dissipated by each resistor true or false?
True. When two resistors of equal value are connected in parallel, the total power dissipated by the circuit is indeed the sum of the power dissipated by each resistor. Since they have the same resistance and are subjected to the same voltage, each resistor will dissipate the same amount of power, and their combined power will equal twice that of one resistor.
