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Voltage times current. You obtain current from the division of voltage and resistance, so:
I[A] = U[V] / R[ohm]
and
P[W] = U[V] * I[A]
it follows, that
P[W] = U[V] * (U[V] / R[ohm]) = U[V] ^ 2 * R[ohm]
So, voltage squared divided by resistance will give you the power that will be dissipated in a resistor. Whether the resistor will take that abuse is up to its power dissipation rating, however.
What else can I help you with?
Which one of the following equations could be used to calculate the power absorbed by a resistor?
p=I*I*R ,P=V*V/R;where I is the current passing through the resistor, and V is the voltage across resistor, and R is the Resistance of the resistor,
How much power in watts is needed to cut a lawn in 50 mins if the work involved is 100000J?
To find the power in watts needed to cut the lawn, you can use the formula ( \text{Power} = \frac{\text{Work}}{\text{Time}} ). Here, the work done is 100,000 J and the time taken is 50 minutes, which is 3,000 seconds. Thus, power required is ( \frac{100,000 , \text{J}}{3,000 , \text{s}} \approx 33.33 , \text{W} ). Therefore, approximately 33.33 watts of power is needed.
Differentiate 2 to the power of x with respect to x?
so say y = 2^x dy/dx = ln2.2^x (. = multiplication symbol, ^ = to-the-power-of symbol) The general formula is (where 'a' is a constant, x is what you are differentiating with respect to and y is f(x)) y = a^x then dy/dx = lna.a^x Go ask a math teacher or look up exponential function differentiation on the internet for why.
What is the formula for finding the future value of a growing annuity?
FV of growing annuity = P * ((1+r)^n - (1+g)^n) / (r-g) P=initial payment r=discount rate or interest rate g=growth rate n=number of periods ^=raised to the power of NB: This formula breaks when r=g due to division by 0. When r=g, use P * n * (1+r)^(n-1)
How many tens are in 4800?
There are 480 tens in 4800. This is because each place value position represents a power of 10, with the tens place representing 10 to the power of 1. Therefore, when you divide 4800 by 10, you get 480, which is the number of tens in 4800.
What is the formula for calculating the power dissipated in a resistor, given the current flowing through it and the resistance value, known as the i2r power?
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
What is the power dissipated by a 1.2 Kilohm resistor if the voltage drop across the resistor is W volts?
The power dissipated by a resistor can be calculated using the formula ( P = \frac{V^2}{R} ), where ( P ) is the power, ( V ) is the voltage drop across the resistor, and ( R ) is the resistance. For a 1.2 kilohm resistor (or 1200 ohms), the power dissipated would be ( P = \frac{W^2}{1200} ) watts. Thus, the power dissipated depends on the square of the voltage drop across the resistor divided by 1200.
If the voltage dropped across a resistor increases by a factor of 10 the power dissipated by the resistor is?
The power dissipated by a resistor is given by the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage across the resistor and ( R ) is its resistance. If the voltage increases by a factor of 10, the new power can be expressed as ( P' = \frac{(10V)^2}{R} = \frac{100V^2}{R} = 100P ). Therefore, the power dissipated by the resistor increases by a factor of 100.
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
If two resistors of equal value are connected in parallel with each other. The power dissipated by the two resistors will be equal to the sum of the power dissipated by each resistor true or false?
True. When two resistors of equal value are connected in parallel, the total power dissipated by the circuit is indeed the sum of the power dissipated by each resistor. Since they have the same resistance and are subjected to the same voltage, each resistor will dissipate the same amount of power, and their combined power will equal twice that of one resistor.
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
Ac power that is converted to heat in a resistor is known as?
real power (as opposed to imaginary power, which is not dissipated)
What is the difference between P I2R or P V 2R?
The formula P = I^2R relates power (P), current (I), and resistance (R), indicating the power dissipated in a resistor. On the other hand, the formula P = V^2/R relates power (P), voltage (V), and resistance (R), representing the power dissipated across a resistor. The former formula deals with power in terms of current, while the latter formula expresses power in terms of voltage.
How do you determine the amperage given the voltage and power dissipated?
Like Ohm's Law, the formula for calculating power is a simple product of two quantities. It is given by the formula P = VI, where V is the voltage in volts and I is the current in amperes (or simply amps). So, if you know the value of any two of the quantities, you can easily calculate the third with simple arithmetic. For example, if the current flowing through a resistor is two amps and the voltage drop across that resistor is five volts, the power dissipated by the resistor is, P = VI = 5 volts * 2 amps = 10 watts. If you are given the power and the voltage, you can easily find the current. For example, if you are told that the voltage drop across a resistor is five volts and is dissipating 10 watts, the current through the resistor is 10 watts/5 volts = 2 amps.
What is power disipated in R if R equals 300 ohms and current equals 20 mA?
The power dissipated in a resistor can be calculated using the formula P = I^2 * R, where P is power, I is current, and R is resistance. Plugging in the values given, we get P = (0.02 A)^2 * 300 ohms = 0.012 watts. Therefore, the power dissipated in the 300-ohm resistor with a current of 20 mA is 0.012 watts.
What power is dissipated by an 8.2 k resistor if a current of 0.005 amps pass's through the resistor?
.205 watts or 205 mw
