answersLogoWhite

0


Want this question answered?

Be notified when an answer is posted

Add your answer:

Earn +20 pts
Q: Can you take a walk in such a way that the distance you cover is greater than the magnitude of your displacement?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What are the data used to calculate for speed?

Distance covered (displacement) and the time taken to cover the distance.


What is velocity and speed?

Speed is a scaler quantity i.e. it has magnitude only without direction. It can be calculated using the formula : speed = distance/time where distance is the total distance travelled from initial position to final position; time is the total time taken to cover this distance. Velocity is a vector quantity i.e. it has magnitude as well as direction. It can be calculated using the formula : velocity = displacement/time displacement is the distance between final position & initial position; time is the total time taken to cover this displacement. for example: if a body starts from some initial point goes to a certain distance x and returns back to the initial position. So the total distance covered is 2x but displacement is 0 (zero) because initial & final position are same. So its speed is 2x/time while velocity is 0/t = 0(zero)


What are two equations for speed?

Speed = (distance covered) divided by (time to cover the distance) Speed = (magnitude of acceleration) multiplied by (time the acceleration has acted)


What are the distance and displacement of the race car drivers in the Indy 500?

To cover the 500-mile distance in the race, the pilots will have to complete 200 laps on the 2.5-mile oval.


How do you calculate magnitude of acceleration without time?

vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a. vf2 = vi2 + 2ad vf2 - vi2 = 2ad (vf2 - vi2)/2d = a


Explain the difference between distance and displacement?

"Displacement" is the shortest possible measurement between the place you started from and the place where you ended up, without regard for the route you took. It's usually the length of a straight line between those two places. "Distance" is how far you actually traveled on the way ... all the twists, turns, curves, switchbacks, hairpins, loops, and doubles. Distance can never be shorter than displacement. The distance you cover in a day is (distance to school) plus (distance back home). But the displacement is zero because you end up exactly where you started.


Define velocity and speed?

Speed is the time rate of change in distance, s= d/t. Velocity is the time rate of change in Displacement v=D/t. The difference is distance d is a real/scalar number and Displacement is a vector number having distance and direction.


What is the relationship between the variables distance and time?

Velocity is a vector, which means it has magnitude and direction. Velocity is defined as the rate of change of displacement (distance), or delta-s over delta-t. In other words, if you divide the distance traveled by the time it took to cover the distance, you know the velocity. For example, if you cover 100 miles (delta-s = 100 miles) in two hours (delta-t = 2 hours), then the velocity is 100/2 = 50 miles per hour. Note that a change in direction also constitutes a change in velocity. But this example concentrates on the magnitude, that is, speed.


How do you convert distance to velocity?

They are incompatible and can't be converted from one another. In order to get a velocity you would also need the time spent to cover the distance. Then you can use the formula distance/time=velocity. For example if you travelled 120 miles in 3 hours, you've travelled at 40 mph. If you have covered 200 kilometers in 4 hours, you've travelled 50 kilometers per hour.


Why do Pluto's revolutions take 249.5 years and Earth's revolutions take 365 days?

Because Pluto has a much greater distance to cover.


Which is the least popular wan standard?

802.11a, because they require a greater density of access points between the wired LAN and wireless clients to cover the same distance that 802.11b networks cover.


An explosion occurs 34Km away Given that sound travels at 340 meter per second and the time it takes for the sound to reach you is?

t = 100 sRecalling that speed or velocity's magnitude v is equal to distance (or displacement)x divided by time t taken to cover that distance: v = x/t, then t = x/v.For this case we have:x = 34 km = 34 000 mv = 340 m/sSo we get:t = (34 000 m)/(340 m/s) = 100 s