Not a good idea, without knowing more about the circuit in which it's installed.
Presumably, the 440v capacitor was selected because its max voltage rating (440v) is
higher than the instantaneous voltage to be expected at that point in the circuit. By that
criterion, the voltage at that point in the circuit may exceed 370 volts, and your proposed
replacement component won't hold it.
It all depends on the application. I would give it a shot and see how it works in your application. If you can measure the current flow with each, that may tell you something about how the larger capacitance might affect the overall operation of your device.
yes
A: the rms value will be169 volts add a capacitor and no load 240 volts and the average will be 153 volts
There are two ways to read this: you have a burned-out run capacitor on your motor and a good start capacitor in your parts box, and you have a burned-out start capacitor and a good run capacitor. If the run capacitor's bad and you want to put the higher-voltage start cap in its place, the answer is yes. This is called derating, and the only thing it does for you is increases the lifespan of the capacitor because you're not working it as hard as it can take. If the start capacitor's bad, don't do this--they used a 440-volt capacitor in there for a reason.
Because the capacitor only needs to "excite" one of the two phases of the 230 volt supply in order to start the motor.
Since there is an AC to DC converter in there, it's hard to say. If it's a basic transformer to rectifier to capacitor design it will put out 6 volts. If it is a transformer to a voltage regulator it's hard to say what will happen. Certainly the drive voltage to the regularor will be cut in half. It may or may not run, but won't be able to run at 12 volts because there won't be any 12 volts to drive the regulator. (There will only be 6 volts.) If it is a switcher it may work fine or it may do nothing.
NO dont do it if you devalue a capacitors voltage parameter what will it do when it is face to face with 20V ? The voltage will destroy the thing. Remember it is OK for you to use a higher voltage parameter for a capacitor but never lower
The 440 volts listed on the cap is the maximum allowable voltage the capacitor can handle. You could actually use a 370 volt cap on 230 volts. ANSWER; 230 volts AC can it actually be 644 volts peak to peak . It is 44ov because it must be rectified and sees only 324 volt peak which is withing the 440 volt capacitor handling voltage
A microfarad measures electrical capacitance. A farad can be defined as the charge in coulombs, which is 1 ampere per second, that a capacitor will accept for the potential across it to charge one volt. A microfarad is equal to one millionth of a farad.
Farad = Coloumb / Volt; solving for Coloumb, you get Coloumb = Farad x Volt. Just plug in the numbers - 1 microfarad is a millionth farad; 0.001 microfarad - if that is what you mean - is 0.000000001 Farad; wherease 1 KV = 1000 Volts.
C=Q/V12 where Q/ V12 is the Charge per Potential Difference between the plates of the capacitor. If you solve for Q, you see that the charge is proportional to this potential difference. You are likely to surpass your load requirements by increasing the charge/discharge amplitude with the 35 volt cap. In other words, your cap will charge up to 35 volts and then discharge that 35 volts onto your load that was set at resonance to operate with 16 volts discharging. Any separation of circuits using this cap would probably fry something on one side or the other over time. Hope this helps.
A: the rms value will be169 volts add a capacitor and no load 240 volts and the average will be 153 volts
No they are not equal680nf = 0.68uf
A volt is a volt is a volt.
A volt is a volt is a volt.
The capacitor blocks the DC portion of the signal and therefore only the AC portion is amplified. i.e if the signal applied exists at a 2 Volt level for instance, after the capacitor the 2 Volts will be trimmed off.
No. The capacitor will short out and possibly explode. On the other hand, the 440 Volt Cap can be used in a 220 Volt circuit.
Nothing will happen, you can go over 6.3v but never under......
There are two ways to read this: you have a burned-out run capacitor on your motor and a good start capacitor in your parts box, and you have a burned-out start capacitor and a good run capacitor. If the run capacitor's bad and you want to put the higher-voltage start cap in its place, the answer is yes. This is called derating, and the only thing it does for you is increases the lifespan of the capacitor because you're not working it as hard as it can take. If the start capacitor's bad, don't do this--they used a 440-volt capacitor in there for a reason.