Explain charging and discharging capacitor

Answer 1

no difference is there. if you connect an uncharged one to a battery/voltage source,current flow will be there for a short time which will tend to charge or in more precise manner will develop charge on its plates.if you connect this charged one to a resister or some load,then capacitor will itself act as a voltage source sending current in the circuit at the expense of the charge present on it.this is discharging current.both are same bunt one tends to put up charge while other does the opposite.

Answer 2

simply put a capacitor will charge from a source as time goes by. the time is specified as R time C. Where Resistance times Capacitance = 63% of the voltage source. Ma thematically it will never reach full charge however for practicability a time of 5 is usually accepted

Answer 3

A capacitor resists a change in voltage. The equation is dv/dt = i/c where dv/dt is volts per second, i is amperes, and c is farads.

If you apply a constant current to a capacitor, it will charge with a linear voltage curve. If you remove a contant current, it will discharge with a linear voltage curve.

If you apply a constant voltage to a capacitor through a resistor, it will charge with a logarithmic voltage curve. This is because the current is constantly changing due to the voltage across the resistor constantly changing.

Answer 4

A capacitor has two large metal foil plates with a thin insulator placed between the plates.It is rolled up like a carpet and is able to store electrical charge on these plates since the insulating 'dielectric' between the plates keeps them apart. Electrolytic capacitor are polarised and must be charged positive plate to the positive of a dc supply like a battery.

An analogy to a capacitor is like a bucket filling with water from a tap (supply of electrons).

A tap turned full on will fill the bucket quickly,A dripping tap will fill the bucket slowly. We now have a means of controlling the charge rate by using a hose(resistor) which we can squeeze (high resistance) or make a larger diameter(low resistance).

Experiment

Take a 6 volt battery, 6 volt flashlight bulb, electrolytic capacitor of about 2000 micro Farad and 3 wires with alligator clips at each end. Now connect the positive of the battery to the positive terminal of the capacitor. From the negative terminal of the battery wire the flashlight bulb in series with the negative terminal of the capacitor.

When you make the final connection the lamp lights very briefly as the discharged capacitor charges through the resistance of the bulb's filament. This is because the two plates have stored electrons from the battery on the plates forming a brief current flow.

The voltage across the capacitor now rises quickly from 0 volts (discharged) to battery voltage (fully charged). Now take the battery away and short the two wires that were across the battery together. The capacitor will make the bulb flash briefly as the charge on the plates discharges through the bulb's filament. We are now able to repeat the experiment but this time adding a resistor. The capacitor charges more slowly as the resistance limits the current flow. It still gets charged but at a much slower rate.

The time, in seconds) needed to charge the capacitor in (Farads) is the Capacitance multiplied by the resistance in (Ohms) or T=CR . Note the time is independent of the voltage applied.

Uses

Capacitors are used in timing circuits as in burglar alarms that allow the homeowner to set the alarm and then quickly leave the house and lock up before the alarm is activated. All this is done as a capacitor is charging inside the alarm circuitry.

Answer 5

Yes, if the charge current is equal to the discharge current.

Answer 6

depends on the load