Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)
The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...
Cd^2+(aq) + S^2-(aq) ==> CdS(s)
What else was your question. This is classed as a double replacement reaction.
2Na+ + CO32- + Sr2+ + 2Cl- --> SrCO3 + 2Na+ + 2Cl- Simplified: Sr2+ + CO32- --> SrCO3 (s)
CuS04 + 2Na -> Na2SO4 + Cu
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
2NH3 + 2NA = 3H2 + NA3N2
The type of reaction represented by Zn plus 2NaCl yields 2Na plus ZnCl2 is an impossible one. It would be the other way around. 2Na + ZnCl2 --------> 2NaCl + Zn
2Na+ + CO32- + Sr2+ + 2Cl- --> SrCO3 + 2Na+ + 2Cl- Simplified: Sr2+ + CO32- --> SrCO3 (s)
single replacment
2Na+I2-->2NaI
CuS04 + 2Na -> Na2SO4 + Cu
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
H2. Hydrogen gas.
2Na + 2H2O -> H2 + 2NaOH
2NaH2 + O2 yields 2Na + 2H2O
Balanced equation for Sodium and Chlorine is: 2Na + Cl2 --> 2NaCl
Combination Reaction