Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]
Ba2++ SO42- --> BaSO4
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
BaCl2+K2SO4=2KCl+BaSO4
BaSO4 + 2CaCl2 --> Ba(Cl2)2 + Ca2SO4
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
BaCl2+K2SO4=2KCl+BaSO4
BaSO4 + 2CaCl2 --> Ba(Cl2)2 + Ca2SO4
Barium sulphate to barium sulphate is NO CHANGE!
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
(NH4)2SO4(aq) + BaCl2(aq) → 2NH4Cl(aq) + BaSO4(s). Barium sulfate is the precipitate.
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
BaCl2(aq) + Na2SO4 (aq) ------> BaSO4(s) + 2NaCl(aq)
Barium chloride can be precipitated wit a sulfate; barium sulfate is then filtrated.
There is no equation in the question, only two pair of two reactants.
Copper nitrate and barium chloride do not react. Barium chloride solution produces a white precipitate with solutions containing sulfate ions.