This question has some missing information but the way you do this problem is to multiply fractions formed by probabilities.
To draw two pens out of the drawer first take the ratio (fraction) of the number of pens over the total number of writing tools. Then, multiply that by one less on the top and the bottom.
Lets say you have 4 pencils, 2 blues and 1 black. Seven total.
2/7*1/6=2/42 probability.
1/15
If you select 45 cards without replacement from a regular deck of playing cards, the probability is 1. For a single randomly selected card, the probability is 2/13.
The probability depends on:whether the cards are drawn randomly,how many cards are drawn, andwhether the cards are replaced before drawing the next card.If only 2 cards are drawn randomly, and without replacement, the probability is 0.00075 approximately.
completely useless.
7
When you pick an object and do not return it, in probability it is termed "without replacement".
If you select 45 cards without replacement from a regular deck of playing cards, the probability is 1. For a single randomly selected card, the probability is 2/13.
The probability depends on:whether the cards are drawn randomly,how many cards are drawn, andwhether the cards are replaced before drawing the next card.If only 2 cards are drawn randomly, and without replacement, the probability is 0.00075 approximately.
The answer depends onwhether the card(s) are drawn from a normal deck of playing cards,whether they are at random,how many cards are drawn,whether the cards are replaced before drawing the next card.Thus, if 49 cards are drawn without replacement from an ordinary deck, whether randomly or not, the probability is 1.For a single card drawn randomly, the probability is 1/13.The answer depends onwhether the card(s) are drawn from a normal deck of playing cards,whether they are at random,how many cards are drawn,whether the cards are replaced before drawing the next card.Thus, if 49 cards are drawn without replacement from an ordinary deck, whether randomly or not, the probability is 1.For a single card drawn randomly, the probability is 1/13.The answer depends onwhether the card(s) are drawn from a normal deck of playing cards,whether they are at random,how many cards are drawn,whether the cards are replaced before drawing the next card.Thus, if 49 cards are drawn without replacement from an ordinary deck, whether randomly or not, the probability is 1.For a single card drawn randomly, the probability is 1/13.The answer depends onwhether the card(s) are drawn from a normal deck of playing cards,whether they are at random,how many cards are drawn,whether the cards are replaced before drawing the next card.Thus, if 49 cards are drawn without replacement from an ordinary deck, whether randomly or not, the probability is 1.For a single card drawn randomly, the probability is 1/13.
completely useless.
If you draw more than 24 cards from a standard pack, without replacement, the probability is 1. That is, it is a certainty. The probability of the outcome for a single, randomly drawn card from a standard pack, is 7/13.
The probability of drawing a queen or king, in a single randomly drawn card, is 2/13. The probability of drawing one when you draw 45 cards without replacement is 1. The probability of choosing has nothing t do with the probability of drawing the card. I can choose a king but fail to find one!
7
When you pick an object and do not return it, in probability it is termed "without replacement".
1/26
The answer depends on how many cards are drawn, and whether they are drawn with or without replacement. If 1 card is drawn, the probability is 0, if 50 cards are drawn (without replacement), the probability is 1. If only two cards are drawn, at random and without replacement, the probability is (4/52)*(3/51) = 12/2652 = 0.0045
If five cards are drawn from a deck of cards without replacement, what is the probability that at least one of the cards is a heart?
hypergeometric distribution f(k;N,n,m) = f(1;51,3,1) or binominal distribution f(k;n,p) = f(1;1,3/51) would result in same probability