abampere
In a water system, the "voltage" is the water pressure, the flow rate is the "current", and the pipe size is the "resistance". Low-voltage electrical current is equivalent to low-pressure water.
It flows through the system and then moves to the left and pi= 3.14 then a dog eats your homework. Whoever reads this is smart.... eyeamawetard!
current decrease
A mechanical wave cannot go to the solar system . But a electromagnet can go all around the world!
It really depends on the system of units used. In the international system (SI), it is a base unit.
Electrical currents are measured in a unit called amperes, which are abbreviated as "amps." There are two different designations that measure currents: direct currents (DC) and alternating currents (AC). Amperes are coulombs per second. Amperes are electrical current units that are part of the meter-kilogram-second system. A flow of one coulomb per second is equivalent to one single ampere.
The centimetre-gram-second system (abbreviated CGS or cgs) is a metric system of physical units based on centimetre as the unit of length, gram as a unit of mass, and second as a unit of time. All CGS mechanical units are unambiguously derived from these three base units, but there are several different ways of extending the CGS system to cover electromagnetism.CGS approach to electromagnetic units The conversion factors relating electromagnetic units in the CGS and SI systems are much more involved - so much so that formulas for physical laws of electromagnetism are adjusted depending on what system of units one uses. refer to link below for methods
Current flow The answer you are looking for is Amperes or Amps. They are used to measure current flow and Amps do the actual work as they move electrons throughout the system.
A coulomb is the quantity of charge displaced by a one ampere per second.
It doesn't 'equate' to current (amperes) because they are two quite different quantities. However, you can find out how much line current is flowing (for a balanced load only) if you divide the number of volt amperes by (1.732 x VL), where VL is the line voltage.
9V by using ohms law
Statcoulumb is the unit of charge in cgs system.
Apparent power is the product of voltage and current in an a.c. system, and is expressed in volt amperes. The rated apparent power of a transformer is the product of its rated secondary current and rated secondary voltage.
There isn't one except by converting all the dimensions in the definition of an ampere into cgs units.
(R) Resistance = (E) Voltage / (I) Current in Amperes R = 12/3 R = 4 ohms
This describes what is known as the 'fault level' at a particular point in an electricity transmission or distribution system, expressed in megavolt amperes, enabling the theoretical value of fault current to be calculated at that point in the system, in order to ensure that the relevant switchgear is capable of interrupting that level of fault current.
You are confusing electrical potential (Volts) and power (Watts). The equation for power (watts) is P = VI where V is volts (a measure of electrical "pressure") and I is current in amperes (the rate of flow of electricity). If the system is 120V and the power used is 600W then the current used is 5A. If the system is 240V and the power used is 600W then the current used is 2.5A.