To solve this you need to remember that chars in C are represented as ints. Because of this property, you can use int comparison operators:
// to test if character c is a letter
int is_alpha(const char c) {
if( c >= 'a' && c <= 'z' )
return 1;
if( c >= 'A' && c <= 'Z' )
return 1;
return 0;
}
// to test if character c is a digit
int is_digit(const char c) {
if( c >= '0' && c <= '9' )
return 1;
return 0;
}
To test for a "special character" you would probably do best writing a similar function which checks for other ASCII value ranges.
1. Get the input- one character from the user
scanf("%c",&ch);
2. check
if((ch>=65)&&(ch<=90))
then print the Character as Upper Case Alphabet
if((ch>=97) &&(ch<=122))
then print the character as Lower Case Alphabet
if((ch>=48) && (ch<=57))
then Numeric
if(((ch>=0)&&(ch<=47))((ch>=58)&&(ch<=64))(ch>=91)&&(ch<=96))(ch>=123)&&(ch<=127)))
then print the character as Special Symbol
3.Terminate the program.
I'll just write a function to do that, I hope the good people won't try to run it as it is.... void function() { char c = 'a'; if( c >= 'a' && c <='z' ) System.out.println("LowerCase"); else if( c>='A' && c <='Z' ) System.out.println("UpperCase"); else System.out.println("Special Character"); }
hey..it s simple..make use of built-in function isdigit(character)..it s in stdlib.h...
its nice
That's easy to do!This script will get the POST data from an HTML form and check if it is a vowel.
It depends on whether the program responds to a hangup signal or not. If you start the program with a 'nohup' command then it will continue to execute.
I'll just write a function to do that, I hope the good people won't try to run it as it is.... void function() { char c = 'a'; if( c >= 'a' && c <='z' ) System.out.println("LowerCase"); else if( c>='A' && c <='Z' ) System.out.println("UpperCase"); else System.out.println("Special Character"); }
hey..it s simple..make use of built-in function isdigit(character)..it s in stdlib.h...
The general solution to this problem is very simple to lay out, but part of it relies on what a "special character" is. The part of code which handles this will be highlighted for the reader to implement as he/she will. void displayType(char c) { if(Character.isUpperCase(c)) { // upper case System.out.println("Upper case"); }else if(Character.isLowerCase(c)) { // lower case System.out.println("Lower case"); } else { // special case // This is where the "special character" part comes in. // You may be defining a "special character" as any non-letter character, // in which case you can simple put the line to print it out in this else // block. A "special character" may also be any non-letter, non-digit // character, and so we would need to check for Character.isDigit at // this point. } }
No. It shows character whether you can get past it.
pinned
An insurance carrier, whether a private carrier or a government program, is referred to as
You can write a program in Turbo C7 that takes a character as input and checks whether it is a vowel or a consonant by using a simple if-else statement. You can compare the input character with a list of vowels (a, e, i, o, u) and if it matches any of these, then it's a vowel; otherwise, it's a consonant. Print the result accordingly.
If you want to check whether a string is a palindrome, you can reverse the string (for example, the Java class StringBuffer has a reverse() method), and then compare whether the two strings - the original string and the reverted string - are equal. Alternately, you could write a loop that checks whether the first character of the string is equal to the last one, the second is equal to the second-last one, etc.; that is, you have a counter variable (in a "for" loop) that goes from zero to length - 1 (call it "i"), and compare character #i with character #(length-i-1) inside the loop.
Whether or not the welfare program is doing its job and not being abused are questions that drives the need for reform. Also, Whether or not the program is successful in helping individuals no longer be dependent on them.
The sentence "Whether he was duplicitous regarding his character is open to question" is grammatically correct and complete.
You can check the value of a character by using if statements.Also, note that this code does not check for capital letters./* code */#include int main(){char c;c = getc(stdin);if (c 'o') {/* If the character is a vowel, this code will be executed. */} else if (c >= 'a' && c
its nice