Yes, it is correct.
It is the Iodine dissolved in aqueous Potassium(or Sodium) Iodide
Zinc Chloride and Iodine
sugar, table salt, sodium sulphate, fructose, potassium chloride, potassium iodide, sodium iodide, uranyl nitrate, etc.
monosodium glutamate, lead diacetate, potassium bitartrate, potassium chloride, magnesium sulfate, sodium chloride, uranyl nitrate, potassium phosphate, etc.
No, like all potassium compounds potassium iodide is ionic.
2KI + Cl2 = 2KCl + I2
This is the correct answer: Cl2(g)+2KI(aq) = I2(s)+2KCl(aq)
Potassium chloride and Iodine
Chlorine, a more reactive halogen would displace iodide in its hallide solution. Potassium chloride would be formed.
In aqueous solution they would not react. They would form a solution of ferric ions, chloride ions, potassium ions, and iodide ions.
Worded Equation; Potassium Iodide + Calcium Chloride ------> Potassium Chloride + Calcium Iodide Chemical Equation; KI (l) + CaCl (l) -----> KCl (aq) + Ca(I)2 (aq) Note Answer is only correct if proper states are applied and used.
Chlorine displaces Potassium Iodide to liberate aqueous I2(brown colour). Hence the solution turns brown.
No - there would be a reaction though if Chlorine and Potassium Iodide were mixed
Displacement scratch that it a single replacement
Here is the equation:Cl2(aq) + 2 KI(aq) ----> 2 KCl(aq) + I2(aq)
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2