HCl + AgNO3 -----> AgCl + HNO3
Zn + 2HCl -----> ZnCl2 + H2
zn is ZINC and hcl is HYDROCHLORIC ACID
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
The reaction is: Zn + 2HCl = ZnCl2 + H2
2Zn(s) + 2HCL (aq) --> 2ZnCl + H2 (g) The reactants are zinc (Zn) and hydrochloric acid (HCl).
Yes, according to the equation Zn (s) + 2HCl (aq) ----> ZnCl2 (aq) + H2 (g).
The net ionic equation is Zn + 2H+ --> Zn2+ + H2
zn is ZINC and hcl is HYDROCHLORIC ACID
yes Zn + 2HCl -> ZnCl2 + H2 is balanced
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
7.3 g of HCl.
The reaction is: Zn + 2HCl = ZnCl2 + H2
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
2Zn(s) + 2HCL (aq) --> 2ZnCl + H2 (g) The reactants are zinc (Zn) and hydrochloric acid (HCl).
Yes, according to the equation Zn (s) + 2HCl (aq) ----> ZnCl2 (aq) + H2 (g).
Balanced equation first. Zn + 2HCl >> ZnCl2 + H2 2.5 mol Zn (2mol HCl/1mol Zn) = 5mol HCl You have 6, so Zn limits. Tried this way. 6 mol HCl (1mol Zn/2mol HCl ) = 3mol Zn you only have 2.5 mol Zn, so again, it limits.
Zn + 2HCl >> ZnCl2 + H2
The Zn starts to bubble, and the HCI faintly evaporates