The Zn starts to bubble, and the HCI faintly evaporates
Zn + HCl ---> ZnCl2 + H2 ZINC CHLORIDE IS THE ANSWER
zn is ZINC and hcl is HYDROCHLORIC ACID
Zn + 2HCl --> ZnCl2 + H2
What does hydrochloric acid cause to be released? When HCl reacts with active metals H2 gas is released Zn + 2 HCl + ZnCl2 + H2 (Gas) When HCL reacts with a carbonate CO2 is realeased CaCO3 + 2 HCl + CaCl2 + H2CO3 H2CO3 releases carbon dioxide H2CO3 = H2O + CO2(Gas)
You get Ammonium Chloride NH3+HCl-- NH4Cl
7.3 g of HCl.
Zn + HCl ---> ZnCl2 + H2 ZINC CHLORIDE IS THE ANSWER
zn is ZINC and hcl is HYDROCHLORIC ACID
Zn + 2HCl --> ZnCl2 + H2
What does hydrochloric acid cause to be released? When HCl reacts with active metals H2 gas is released Zn + 2 HCl + ZnCl2 + H2 (Gas) When HCL reacts with a carbonate CO2 is realeased CaCO3 + 2 HCl + CaCl2 + H2CO3 H2CO3 releases carbon dioxide H2CO3 = H2O + CO2(Gas)
Hydrogen is produced, as illustrated with the metal zinc: Zn + 2 HCl -> ZnCl2 + H2.
You get Ammonium Chloride NH3+HCl-- NH4Cl
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
The reaction is: Zn + 2HCl = ZnCl2 + H2
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
2Zn(s) + 2HCL (aq) --> 2ZnCl + H2 (g) The reactants are zinc (Zn) and hydrochloric acid (HCl).
Yes, according to the equation Zn (s) + 2HCl (aq) ----> ZnCl2 (aq) + H2 (g).