One liter of Benedict's solution contains 173 grams sodium citrate, 100 grams sodium carbonate, and 17.3 grams cupric sulfate pentahydrate.
It is normally benedicts solution. Add about 1/4 of the total sugar solution to a test tube and heat it in a hot water bath at around 50 degrees C for 5 min. For example, heat 40mL of sugar water (C12H22O11 aq ) with 10mL of Benedicts soluton (copper and sodium salts). If it is a positive test it will turn yellow.
These solutions contain 1 mol of the particular substance dissolved in a liter of water.
342 grams of Lactose in 1 litre water or 34.2 grams in 100 mls.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
To prepare a 1000 ppm (parts per million) solution of KMnO4 (potassium permanganate), you need 1000 mg of KMnO4 per liter of solution. Since 1 gram equals 1000 mg, you would need 1 gram of KMnO4 dissolved in enough water to make a final volume of 1 liter. Therefore, to prepare a 1000 ppm solution, dissolve 1 gram of KMnO4 in 1 liter of water.
A normal solution is a solution in which 1 gram of solute is dissolved in 1 liter of water
Depends on the concentration of the solution and what is in it.
It is normally benedicts solution. Add about 1/4 of the total sugar solution to a test tube and heat it in a hot water bath at around 50 degrees C for 5 min. For example, heat 40mL of sugar water (C12H22O11 aq ) with 10mL of Benedicts soluton (copper and sodium salts). If it is a positive test it will turn yellow.
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
These solutions contain 1 mol of the particular substance dissolved in a liter of water.
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
What volume of this solution do you desire? Let's say you want to make 1 liter of such a solution. You would weigh out 1 gram (1000 mg) of NaCl and dissolve it in enough water to make a final volume of 1 liter (1000 ml). Since 1000 ppm means 1000 mg/liter, this is how you make 1 liter of that solution. For larger or smaller volumes, adjust appropriately.
To prepare a 1 liter of 100ppm NaCl solution, you would dissolve 0.1 grams of NaCl in 1 liter of water. This concentration is achieved by mixing 0.1 grams of NaCl in 1 liter of water.
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
1 mole of glucose contains 6.022 x 10^23 molecules. In a 1 M solution, there would be 1 mole of glucose dissolved in 1 liter of solution, so there would be 6.022 x 10^23 molecules of glucose in 1 liter of the solution.
Assuming that the density of the solution in 1 gdm-3 : 1 litre = 1dm3= 1 kg = 1000g
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.