One liter of Benedict's solution contains 173 grams sodium citrate, 100 grams sodium carbonate, and 17.3 grams cupric sulfate pentahydrate.
It is normally benedicts solution. Add about 1/4 of the total sugar solution to a test tube and heat it in a hot water bath at around 50 degrees C for 5 min. For example, heat 40mL of sugar water (C12H22O11 aq ) with 10mL of Benedicts soluton (copper and sodium salts). If it is a positive test it will turn yellow.
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
You add 9.09ml of stock solution to a volumetric and make it up to 1 litre to get a 110 dilution
Depends on the material in question.
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
It would be 0.1M HCl solution. In 1 liter there would be 3.65 g of HCl and the balance would be water.
A normal solution is a solution in which 1 gram of solute is dissolved in 1 liter of water
Depends on the concentration of the solution and what is in it.
It is normally benedicts solution. Add about 1/4 of the total sugar solution to a test tube and heat it in a hot water bath at around 50 degrees C for 5 min. For example, heat 40mL of sugar water (C12H22O11 aq ) with 10mL of Benedicts soluton (copper and sodium salts). If it is a positive test it will turn yellow.
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
What volume of this solution do you desire? Let's say you want to make 1 liter of such a solution. You would weigh out 1 gram (1000 mg) of NaCl and dissolve it in enough water to make a final volume of 1 liter (1000 ml). Since 1000 ppm means 1000 mg/liter, this is how you make 1 liter of that solution. For larger or smaller volumes, adjust appropriately.
Assuming that the density of the solution in 1 gdm-3 : 1 litre = 1dm3= 1 kg = 1000g
The molarity is 2,973.
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The formula is C6H12O6 which is 180g/mole. Divide that in half for 90g in one liter of water for a 0.5 molar solution
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